OEIn the question, you are given that \(x = 7n + 2\) and \(y = 6n + 3\). Substituting the given expressions for x and y in Quantity A, you get \(x + y = 13n + 5.\) Using trial and error, you can compare Quantity A, the ones digit of \(13n + 5,\) and Quantity B, 5, by plugging in a few values for the positive integer n.
If \(n = 1,\) then \(x + y = 18\) and the ones digit is 8, which is greater than 5. So in this case Quantity A is greater than Quantity B.
If \(n = 2,\) then \(x + y = 31\) and the ones digit is 1, which is less than 5. So in this case Quantity B is greater than Quantity A.
Since in one case Quantity A is greater than Quantity B, and in the other case Quantity B is greater than Quantity A, you can conclude that the correct answer is Choice D.