(10-w)(9-w) < 9 ... implies w > 6 ...how?
w(w-1) > 45 ..implies w>7...how?
(10-w)(9-w) < 9
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90 -19w + w^2 < 9
w^2 -19w + 81 < 0
roots will be close to 6.5 and 12.5
(w-6.5) * (w-12.5) < 0
So either (w-6.5) < 0 and (w-12.5) > 0
or (w-6.5) > 0 and (w-12.5) < 0
(w-6.5) < 0 and (w-12.5) > 0
=> w <6.5 and w > 12.5 NO intersection between these two so no solution
(w-6.5) > 0 and (w-12.5) < 0
=> w > 6.5 and w< 12.5
=> 6.5 < w < 12.5
So if w is integer then 7 <= w <= 12
w(w-1) > 45
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w^2 - w - 45 > 0
roots will be close to 7.25 and -6.25
So, (w - 7.25) * (w + 6.25) > 0
So either both the terms are > 0 or both are < 0
(w - 7.25) < 0 and (w + 6.25) < 0
=> w < 7.25 and w < -6.25 Intersection is w < -6.25
(w - 7.25) > 0 and (w + 6.25) > 0
=> w > 7.25 and w > -6.25
Intersection is w > 7.25
So, answer for second equation is w < -6.25 and w > 7.25
Hope it helps!