Last visit was: 17 May 2026, 17:33 It is currently 17 May 2026, 17:33
Home
Messages
Tests
Schools
Events
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel
User avatar
bmwhype2
User avatar
Joined: 21 Jan 2007
Last visit: 08 Mar 2010
Posts: 1,333
Own Kudos:
5,569
Given Kudos: 4
Location: New York City
Posts: 1,333
Kudos: 5,569
not quite getting the logic of the explanation IF the sum of 19 May 2007, 16:25
Kudos
Add Kudos
Bookmarks
Bookmark this Post
not quite getting the logic of the explanation

IF the sum of 5 consecutive positive integers is A, the the sum of the next five consecutive intergers in terms of A is

1 a+1
2 a+5
3 a+25
4 2a
5 5a



Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block below for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
User avatar
gowani
User avatar
Joined: 17 May 2007
Last visit: 17 Feb 2022
Posts: 51
Own Kudos:
106
Posts: 51
Kudos: 106
not quite getting the logic of the explanation IF the sum of 19 May 2007, 16:31
Kudos
Add Kudos
Bookmarks
Bookmark this Post
did some trail and error; it seems a+25 seems accurate...i'm going for #3
User avatar
gmatiscoming
User avatar
Joined: 04 May 2007
Last visit: 28 Aug 2007
Posts: 71
Own Kudos:
27
Posts: 71
Kudos: 27
not quite getting the logic of the explanation IF the sum of Updated on: 19 May 2007, 17:42
Originally posted by gmatiscoming on 19 May 2007, 17:01.
Last edited by gmatiscoming on 19 May 2007, 17:42, edited 1 time in total.
Kudos
Add Kudos
Bookmarks
Bookmark this Post
so here's what i did:

sum of the first consecutive 5 numbers =

n + (n+1) + (n+2) + (n+3) + (n+4) = 5n+10

n could be anything, and n+1 is always the next integer and so on....

next 5 numbers:

n+5 + n+6 + n+7 + n+8 n+9 = 5n+35

mistakenly i thought i was finished then i looked at the answer choices and then i realized i was wrong and finished it up by recognizing:

if A = 5n+10 (the first five numbers)

5n+35 in terms of A is A+25. (5n+10 +25)


Choice C. hope that helps and hoped i explained it well enough for you! i;ve got a question posted about sets that is really bothering me check it out and let me know if you understand what i am asking. i hate when people give you an answer as a stritng of numbers but don't understand logic behind anything....
User avatar
Himalayan
User avatar
Joined: 26 Feb 2006
Last visit: 09 Aug 2011
Posts: 383
Own Kudos:
634
Posts: 383
Kudos: 634
not quite getting the logic of the explanation IF the sum of 19 May 2007, 17:17
Kudos
Add Kudos
Bookmarks
Bookmark this Post
gmatiscoming
so here's what i did:

sum of the first consecutive 5 numbers =

n + (n+1) + (n+2) + (n+3) + (n+4) = 5n+10

n could be anything, and n+1 is always the integer # and so on....

next 5 numbers:

n+5 + n+6 + n+7 + n+8 n+9 = 5n+35

mistakenly i thought i was finished then i looked at the answer choices and then i realized i was wrong and finished it up by recognizing:

if A = 5n+10 (the first five numbers)

5n+35 in terms of A is A+25. (5n+10 +25)


Choice C. hope that helps and hoped i explained it well enough for you! i;ve got a question posted about sets that is really bothering me check it out and let me know if you understand what i am asking. i hate when people give you an answer as a stritng of numbers but don't understand logic behind anything....
Show more


perfect


first = f
last = l
n = 5
sum = n(f+l)/2 = 5(f+l)/2 =(5f+5l)/2

next 5 integers:
F = f+5
L = l+5
n = 5
sum = n(F+L)/2 = 5 (f+5+l+5)/2 = (5f+5l+50)/2 = [(5f+5l)/2] + [50/2]

now, [(5f+5l)/2] + [50/2] = a + 25
User avatar
mNeo
User avatar
Current Student
Joined: 22 Apr 2007
Last visit: 04 Sep 2009
Posts: 1,034
Own Kudos:
30
Posts: 1,034
Kudos: 30
not quite getting the logic of the explanation IF the sum of 19 May 2007, 17:30
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Let the first number be u
u + (u+1) + .. + (u+4) = a
5u + 10 = a

Similarly, for the next five numbers,
5u + 5 + .. + 9
= 5 u + 35
= a + 25
User avatar
vikramjit_01
User avatar
Joined: 02 Jan 2007
Last visit: 22 Aug 2009
Posts: 162
Own Kudos:
41
Posts: 162
Kudos: 41
not quite getting the logic of the explanation IF the sum of 19 May 2007, 18:00
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Here's one more...

Each number in the series is increasing by 5. And there are 5 numbers in the series so the total increase is
5*5 = 25

So if you had A earlier you'll have A+25 now.
User avatar
GMATBLACKBELT
User avatar
Joined: 29 Mar 2007
Last visit: 03 Jun 2013
Posts: 1,138
Own Kudos:
1,916
Posts: 1,138
Kudos: 1,916
not quite getting the logic of the explanation IF the sum of 19 May 2007, 23:55
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Can you guys point me to some math fundamentals here. Where do u find out all these basic things like n+1, n+2, etc... and its all fancy.


I just did this 1+2+3+4+5=15

6+7+8+9+10=40

40-15=25... thus A+25...



Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!