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saxenashobhit
From equation 1 x=2, x=-2

From equation 2; x=2 and x=1

So union has 3 solutions

How to solve B
\(x^2\)-2x-x+2=0
So (x-2)(x-1)=0

How do we convert \(x^2\)-2x-x+2=0 to (x-2)(x-1)=0 ?
little rusty with algebra.


(x-2)(x-1) so lets FOIL.
x*x + x(-1) + (-2 *x) + (-2*-1) = x^2 -x -2x +2 = x^2 -3x +2
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greatchap
Hi Guys,

How can I solve the following question ?

Q-1) If a is the solution of the equation x^2 - 4 = 0 and B is the solution set of the equation x^2 - 3x + 2=0, how many elements are in the union of the two sets.

OA is : 3

I am unable to solve B.

Please advice.

Thanks,

Cheers,
GR

Seems that you need to brush up on quadratics.

Solving Quadratic Equations: https://www.purplemath.com/modules/solvquad.htm

Factoring Quadratics: https://www.purplemath.com/modules/factquad.htm

Good links with several different approaches.

Hope it helps.
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greatchap
saxenashobhit
From equation 1 x=2, x=-2

From equation 2; x=2 and x=1

So union has 3 solutions

How to solve B
\(x^2\)-2x-x+2=0
So (x-2)(x-1)=0

How do we convert \(x^2\)-2x-x+2=0 to (x-2)(x-1)=0 ?
little rusty with algebra.


(x-2)(x-1) so lets FOIL.
x*x + x(-1) + (-2 *x) + (-2*-1) = x^2 -x -2x +2 = x^2 -3x +2

Dude, I know how to solve (X-2) (x-1). I wanted to know how to convert \(x^2\)-2x-x+2=0 to (x-2)(x-1)

Now i know, read content on factoring.
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Thanks Bunuel for help on algebra.



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