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12 Aug 2008, 10:32
Kudos
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OA to follow.....
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mba9now
Boss... please type the question..
intersect x axis when y=0
(x+a)(x+b)=0
--> two points are .. (-a,0) and (-b,0)
1) a+b=-1
--> one equation two variable..s
Not suffciient
2) graph intersect y at (0,-6)
orignal equation y=(x+a)(x+b)
-6=(0+a) (0+b) --> ab=-6
Not suffcieint
combine both
a+b=-1
ab=-6
a-6/a=-1
a^2-6+a=0
--> a*a+3a-2a-6 =0 --> a(a+3)-2(a+3) ===>
(a+3)(a-2)=0
a=-3 or a=2
substitue values in a+b=-1
a=-3 b=2
a=2 b=-3
(both solutions are same )
suffcieint
C
