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Of the 100 athletes at a soccer club, 40 play defense and 70

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Of the 100 athletes at a soccer club, 40 play defense and 70 [#permalink]

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Of the 100 athletes at a soccer club, 40 play defense and 70 play midfield. If at least 20 of the athletes play neither midfield nor defense, the number of athletes that play both midfield and defense could be any number between

A. 10 to 20
B. 10 to 40
C. 30 to 40
D. 30 to 70
E. 40 to 70
[Reveal] Spoiler: OA

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Re: Of the 100 athletes at a soccer club, 40 play defense and 70 [#permalink]

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Mountain14 wrote:
Of the 100 athletes at a soccer club, 40 play defense and 70 play midfield. If at least 20 of the athletes play neither midfield nor defense, the number of athletes that play both midfield and defense could be any number between

A. 10 to 20
B. 10 to 40
C. 30 to 40
D. 30 to 70
E. 40 to 70


First of all notice that since only 40 athletes play defense, then the number of athletes that play both midfield and defense cannot possibly be greater than 40. Eliminate D and E.

{Total} = {defense} + {midfield} - {both} + {neither}

100 = 40 + 70 - {both} + {neither}

{both} = {neither} + 10.

Since the least value of {neither} is given to be 20, then the least value of {both} is 20+10=30. Eliminate A and B.

Answer: C.
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Re: Of the 100 athletes at a soccer club, 40 play defense and 70 [#permalink]

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Refer diagram below

We require to find the shaded region

Setting up the equation

40 + 70-x + 20 = 100

x = 30

For defence = 40; the maximum value for which x can reach is also 40

Range = 30 to 40

Answer = C
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foot.png [ 4.77 KiB | Viewed 1837 times ]


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Re: Of the 100 athletes at a soccer club, 40 play defense and 70 [#permalink]

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Re: Of the 100 athletes at a soccer club, 40 play defense and 70 [#permalink]

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Mountain14 wrote:
Of the 100 athletes at a soccer club, 40 play defense and 70 play midfield. If at least 20 of the athletes play neither midfield nor defense, the number of athletes that play both midfield and defense could be any number between

A. 10 to 20
B. 10 to 40
C. 30 to 40
D. 30 to 70
E. 40 to 70


Fill the attached table and ull get the answer in less than a min

Since max number of athletes who can play defense s only 40, after filling the table u can conclude that the (c) 30 to 40 is the answer
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Screenshot_2015-09-12-13-01-11.png [ 72.94 KiB | Viewed 1264 times ]

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Re: Of the 100 athletes at a soccer club, 40 play defense and 70 [#permalink]

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New post 09 Aug 2017, 04:22
Hello from the GMAT Club BumpBot!

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Re: Of the 100 athletes at a soccer club, 40 play defense and 70 [#permalink]

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HarveyS wrote:
Of the 100 athletes at a soccer club, 40 play defense and 70 play midfield. If at least 20 of the athletes play neither midfield nor defense, the number of athletes that play both midfield and defense could be any number between

A. 10 to 20
B. 10 to 40
C. 30 to 40
D. 30 to 70
E. 40 to 70


Here is how you can think about it:

We are given the minimum value of "Neither" and we need to find the minimum and maximum value of "Both".

Total = A + B - Both + Neither

Both = 40 + 70 - 100 + Neither

Both = 10 + Neither

Minimum value of Neither is 20.

Maximum value of Neither will be obtained when "defense" circle in inside the "midfield" circle. So 100 - 70 = 30 would be Neither.

So minimum value of Both is 10+20 = 30 and maximum value is 10+30 = 40.

Answer (C)
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Re: Of the 100 athletes at a soccer club, 40 play defense and 70   [#permalink] 09 Aug 2017, 04:46
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