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# Of the following, which is the closest approximation of (0.011^2*4.75)

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Math Expert
Joined: 02 Sep 2009
Posts: 50009
Of the following, which is the closest approximation of (0.011^2*4.75)  [#permalink]

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08 Nov 2016, 01:20
00:00

Difficulty:

35% (medium)

Question Stats:

71% (02:00) correct 29% (02:21) wrong based on 168 sessions

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Of the following, which is the closest approximation of $$\frac{(0.011^2*4.75)}{(1.02*0.0002)}$$?

A. 0.0056
B. 0.028
C. 0.056
D. 2.8
E. 5.6

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Posts: 259
Location: India
Concentration: Operations, Strategy
Schools: ISB '18 (D)
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Re: Of the following, which is the closest approximation of (0.011^2*4.75)  [#permalink]

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08 Nov 2016, 02:11
Bunuel wrote:
Of the following, which is the closest approximation of $$\frac{(0.011^2*4.75)}{(1.02*0.0002)}$$?

A. 0.0056
B. 0.028
C. 0.056
D. 2.8
E. 5.6

IMO D
(11*11*10^-6*19)/(4*102*2*10^-6)= (121*19)/(8*102)
approximating we get 2300/(100*8)
which is approximately 2.8
Manager
Joined: 11 Jun 2017
Posts: 76
Re: Of the following, which is the closest approximation of (0.011^2*4.75)  [#permalink]

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21 Nov 2017, 13:36
Bunuel wrote:
Of the following, which is the closest approximation of $$\frac{(0.011^2*4.75)}{(1.02*0.0002)}$$?

A. 0.0056
B. 0.028
C. 0.056
D. 2.8
E. 5.6

Hi Bunuel,

Can you please provide some basic tips to keep in mind while approximating ? Is there anything in specific for this.

Thanks
Math Expert
Joined: 02 Sep 2009
Posts: 50009
Re: Of the following, which is the closest approximation of (0.011^2*4.75)  [#permalink]

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21 Nov 2017, 21:07
1
1
Poorvasha wrote:
Bunuel wrote:
Of the following, which is the closest approximation of $$\frac{(0.011^2*4.75)}{(1.02*0.0002)}$$?

A. 0.0056
B. 0.028
C. 0.056
D. 2.8
E. 5.6

Hi Bunuel,

Can you please provide some basic tips to keep in mind while approximating ? Is there anything in specific for this.

Thanks

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Hope it helps.
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Re: Of the following, which is the closest approximation of (0.011^2*4.75)  [#permalink]

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21 Nov 2017, 21:37
Bunuel wrote:
Of the following, which is the closest approximation of $$\frac{(0.011^2*4.75)}{(1.02*0.0002)}$$?

A. 0.0056
B. 0.028
C. 0.056
D. 2.8
E. 5.6

I will approximate to:

$$\frac{120}{200} * 4.75$$. A little more than half of 4.75; D seems right.
Re: Of the following, which is the closest approximation of (0.011^2*4.75) &nbs [#permalink] 21 Nov 2017, 21:37
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