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Of the three numbers, median is M and average is A, is

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Current Student
Joined: 11 May 2008
Posts: 552
Of the three numbers, median is M and average is A, is [#permalink]

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31 Jul 2008, 10:41
Of the three numbers, median is M and average is A, is M<A?
(1) M is less than the average of the largest and smallest number.
(2) The largest number is 250 greater than the average, and the smallest number is 150 less than the average.
A. Statement (1) ALONE is sufficient but Statement (2) ALONE is not sufficient.
B. Statement (2) ALONE is sufficient but Statement (1) ALONE is not sufficient.
C. BOTH Statements TOGETHER are sufficient, but NEITHER Statement alone is sufficient.
D. Each Statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.

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Intern
Joined: 28 May 2008
Posts: 7
Re: median , and mode [#permalink]

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31 Jul 2008, 11:20

1.For 1 3 9
Is M < A -> Yes
For 1 2 4
Is M < A -> No
Insufficient

2. Lets say A = 100
based on given condition -50 Y 350
Y could be anything
Insufficient

If you combine 1 & 2, still Insufficient
Senior Manager
Joined: 23 May 2006
Posts: 311
Re: median , and mode [#permalink]

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31 Jul 2008, 11:30
Of the three numbers, median is M and average is A, is M<A?
(1) M is less than the average of the largest and smallest number.
(2) The largest number is 250 greater than the average, and the smallest number is 150 less than the average.

S2. Let the three numbers be x,y,z in ascendign order; In this case y will be the median
Average = x+y+z/3 = A
z = A+250 and x = A -150

3A = A-150 + y + A+250
A = y + 100
Hence average is greater than the median A> M; so ACE are out BD in

S1. y < x+z/2 You can pick numbers here

10, 11, 29 M < A
6, 7, 18 M < A

IMO D
SVP
Joined: 07 Nov 2007
Posts: 1760
Location: New York
Re: median , and mode [#permalink]

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31 Jul 2008, 11:36
arjtryarjtry wrote:
Of the three numbers, median is M and average is A, is M<A?
(1) M is less than the average of the largest and smallest number.
(2) The largest number is 250 greater than the average, and the smallest number is 150 less than the average.
A. Statement (1) ALONE is sufficient but Statement (2) ALONE is not sufficient.
B. Statement (2) ALONE is sufficient but Statement (1) ALONE is not sufficient.
C. BOTH Statements TOGETHER are sufficient, but NEITHER Statement alone is sufficient.
D. Each Statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.

say X and Y are smallest and largest numbers

A= (X+Y+M)/3
X+Y+M=3A
1) M<(X+Y)/2 --suffciient
X+Y>2M
X+Y+M>3M
3A>3M
A>M -->M<A
2) Y= A+250 -- Sufficient.
X= A-150
X+Y+M=3A --> 2A+100+M=3A
--> A=M+100
--> M<A

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VP
Joined: 17 Jun 2008
Posts: 1322
Re: median , and mode [#permalink]

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03 Aug 2008, 07:17
[quote="arjtryarjtry"]Of the three numbers, median is M and average is A, is M x+y+m 31 a sufficient

(2) solving condn in (2) we get m=a-100 => m sufficient

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Re: median , and mode   [#permalink] 03 Aug 2008, 07:17
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Of the three numbers, median is M and average is A, is

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