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19 Mar 2008, 21:58
Kudos
Bookmarks
Hey all, I am a forum noob.. I need help with this question:
OG 11 Dianostic Test Quan #16 help p. 22
Square root of (3-2x) = square root of (2x) + 1 ----- only the 2x has the square root sign
1
4
2-2x
4x-2
6x-1 (answer)
I read the answer explanations but I am still having problems understanding it.. I don't get the explanation of squaring both sides to equal
3-2x=2x +2 square root (2x) + 1
Where does the 2x in the second equation come from???
Thanks in advance.
Kim
OG 11 Dianostic Test Quan #16 help p. 22
Square root of (3-2x) = square root of (2x) + 1 ----- only the 2x has the square root sign
1
4
2-2x
4x-2
6x-1 (answer)
I read the answer explanations but I am still having problems understanding it.. I don't get the explanation of squaring both sides to equal
3-2x=2x +2 square root (2x) + 1
Where does the 2x in the second equation come from???
Thanks in advance.
Kim
Archived Topic
Hi there,
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19 Mar 2008, 22:05
Kudos
Bookmarks
\(\sqrt{3-2x}=\sqrt{2x}+1\)
\((\sqrt{3-2x})^2=(\sqrt{2x}+1)^2\)
\(3-2x=2x+2\sqrt{2x}+1\)
\((\sqrt{3-2x})^2=(\sqrt{2x}+1)^2\)
\(3-2x=2x+2\sqrt{2x}+1\)
19 Mar 2008, 22:12
Kudos
Bookmarks
thx for clarifying my post, not sure how to do that yet 
Anyway, where does the extra 2x come from in the second line? I know it must be fairly elementary, but I am not getting it! Thanks again..
Anyway, where does the extra 2x come from in the second line? I know it must be fairly elementary, but I am not getting it! Thanks again..
