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OG 11 PS #173

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OG 11 PS #173 [#permalink]

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New post 07 Mar 2009, 02:09
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A
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C
D
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If a/b = 2/3, which of the following is NOT true?

(A) (a+b)/b = 5/3

(B) b/(b-a) = 3

(C) (a-b)/b = 1/3

(D) 2a/3b = 4/9

(E) (a+3b)/a = 11/2

The OG's method of solving this is slightly involved. But...assuming a question like this, in which the answer choices do *not* have any exponents, one could just directly substitute a in for 2, and b in for 3...always, ...right?

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Re: OG 11 PS #173 [#permalink]

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New post 07 Mar 2009, 03:53
Let a=2 and b=3 (since a/b = 2/3)

Start with option (E)
a+3b/a = 2+9/2 = 11/2 ----> hence true

option (D)
2a/3b = 4/9 --> hence correct

option (C)
(a-b)/b = 2-3/3 = -1/3 ---> hence "Not True"

Therefore, C is the answer.
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Re: OG 11 PS #173 [#permalink]

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New post 07 Mar 2009, 04:35
why cant we directly substitute values if we have exponents in answers?
mmace1 wrote:
If a/b = 2/3, which of the following is NOT true?

(A) (a+b)/b = 5/3

(B) b/(b-a) = 3

(C) (a-b)/b = 1/3

(D) 2a/3b = 4/9

(E) (a+3b)/a = 11/2

The OG's method of solving this is slightly involved. But...assuming a question like this, in which the answer choices do *not* have any exponents, one could just directly substitute a in for 2, and b in for 3...always, ...right?

Kudos [?]: 510 [0], given: 0

Re: OG 11 PS #173   [#permalink] 07 Mar 2009, 04:35
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OG 11 PS #173

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