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OG 11 #99

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Director
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OG 11 #99 [#permalink]

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New post 03 May 2009, 12:39
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On a scale that measures the intensity of a certain phenomenon, a reading of n+1 corresponds to an intensity that is 10 times the intensity corresponding to a reading of n. On that scale, the intensity corresponding to a reading of 8 is how many times as great as the intensity corresponding to a reading of 3?

A) 5
B) 50
C) 10^5
D) 5^10
E) 8^10-3^10

can some one please show the steps used to to solve this one. thanks
VP
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Concentration: General Management, Strategy
Schools: Duke (Fuqua) - Class of 2012
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Re: OG 11 #99 [#permalink]

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New post 03 May 2009, 13:01
C

This is a log10 scale measurement

Let's say n=1 will register an intensity of 10
then n+1=2 will register an intensity of 100

the formula that correspond the reading to the intensity is 10^(reading)

10^8/10^3=10^(8-3)=10^5
Director
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Re: OG 11 #99 [#permalink]

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New post 03 May 2009, 13:04
asimov wrote:
C

This is a log10 scale measurement

Let's say n=1 will register an intensity of 10
then n+1=2 will register an intensity of 100

the formula that correspond the reading to the intensity is 10^(reading)

10^8/10^3=10^(8-3)=10^5


ok..got it..thanks!
Director
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Location: Kolkata,India
Re: OG 11 #99 [#permalink]

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New post 05 May 2009, 00:15
My solution:
according to the stem:
READING.........................VALUE
n..................................x
n+1..............................10x
n+2..............................100x
n+3...............................1000x

so,let n=x=1.Therefore,following the above pattern:
1............................1
2.............................10
3..............................100
4...............................1000

Reading of 8=10^7
Reading of 3=10^2

QUERIE:How is 10^7 10^5 times greater than 10^2??should'nt the answer be 10^7-10^2.Seems to me that instead of substracting,we are dividing. why?this is not clear.
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http://gmatclub.com/forum/countdown-beginshas-ended-85483-40.html#p649902

Director
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Joined: 23 May 2008
Posts: 799
Re: OG 11 #99 [#permalink]

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New post 05 May 2009, 00:32
tejal777 wrote:
My solution:
according to the stem:
READING.........................VALUE
n..................................x
n+1..............................10x
n+2..............................100x
n+3...............................1000x

so,let n=x=1.Therefore,following the above pattern:
1............................1
2.............................10
3..............................100
4...............................1000

Reading of 8=10^7
Reading of 3=10^2

QUERIE:How is 10^7 10^5 times greater than 10^2??should'nt the answer be 10^7-10^2.Seems to me that instead of substracting,we are dividing. why?this is not clear.

it says how many times greater so it would be 10^7/10^2= 10^7-2= 10^5
Re: OG 11 #99   [#permalink] 05 May 2009, 00:32
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