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ugo_castelo
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OA is C

Congratulations
solving each equation from each statement, I get points (-7,-19) and (8,26)

Combining St1 and St2 I get y=3x +2

How did you get point (1,5)?

thanks
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GMATT73......WOULD YOU PL EXPLAIN HOW WE GOT THE C

IN MORE DETAILS MAN ...I VE GOT A PERSONAL PROBLEM WITH COORDINATE GEOMETRY :lol:

HELP
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Ok I went with this question a really long way so DON'T DO that haha!

I basically opened up the terms for both the equations and subtracted the 2nd equation from the first, lot of terms cancel out. In the end, you get an equation of form

s=3r+2 which is the same as eq in the question.

But however , I'd like to know what the short cut is :) Matt can you please provide your explaination how you got your answer coz I seriously can't spend so much time like this on the exam :cry:
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cicerone
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Does y=3x+2 contain (r,s)?

It is C.
Statement 1: (3r+2-s)(4r+9-s)=0
So either (3r+2-s) = 0 or (4r+9-s)=0
If 3r+2-s =0
ie s= 3r+2 which mean y=3x+2 contain (r,s)

But if (4r+9-s) =0 then y=3x+2 does not contain (r,s).

So (1) is not sufficient.

Statement 2: (4r-6-s)(3r+2-s) = 0
Thinking along the same lines (2) is not sufficient.

If we combine both (3r+2-s) must be 0
Hence the line contains (r,s)
So it is C
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It's clear...

Thanks

However you need some imagination to get to this conclusion



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