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# OG PS#72

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Director
Joined: 25 Oct 2008
Posts: 591
Location: Kolkata,India
OG PS#72 [#permalink]

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04 May 2009, 20:53
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Atleast 2/3 of the 40 members of a committee must vote in favour of a resolution for it to pass.What is the greatest number of members who could vote against the resolution and still have it pass?
A. 19
B. 17
C. 16
D. 14
E. 13

I keep on getting this ques. wrong i don't know why.Here's my solution:
2/3 x 40=2 x 13.333.. = 2 x 13 =26
Therefore, 26 are in favour and 14 are against.Ans:14.WRONG.

However if we approach the other way around and start by calculating members against the resolution,
1/3 x 40=13.333..=13.Ans: 13 which is the correct ans.

Can somebody please point out the flaw?
_________________

http://gmatclub.com/forum/countdown-beginshas-ended-85483-40.html#p649902

Intern
Joined: 02 Feb 2009
Posts: 36
Re: OG PS#72 [#permalink]

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04 May 2009, 21:14
you made 2 mistakes: you rounded at the wrong point and you rounded in the wrong direction. Never round mid problem, you lose information and you can alter your results.

Also, remember youre talking about votes, so when they say at least 2/3 you cant have fractions of a vote and you cant simply round to the closest number.

You must pay attention to the at least part. "At least" 2/3 of 40 is 26.66 ==> 27 or more votes to pass. This means that it will still pass with 13 votes against it.

Please note I didnt simply round to the closest integer. If the fractions gave the result of AT LEAST 26.1 it would still imply that they require 27 votes to pass.

hope that clears it up!
millhouse
Re: OG PS#72   [#permalink] 04 May 2009, 21:14
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# OG PS#72

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