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### Show Tags

27 Dec 2017, 01:10
00:00

Difficulty:

15% (low)

Question Stats:

93% (00:50) correct 7% (01:17) wrong based on 43 sessions

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On 3 sales Tom has received commissions of $250,$95, and $175, and has two additional sales pending. If Tom is to receive an average (arithmetic mean) commission of exactly$150 on the 5 sales, then the average (arithmetic mean) of the final two sales must be

A. 60
B. 80
C. 115
D. 230
E. 280

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Joined: 07 Dec 2017
Posts: 589

### Show Tags

27 Dec 2017, 11:34
Bunuel wrote:
On 3 sales Tom has received commissions of $250,$95, and $175, and has two additional sales pending. If Tom is to receive an average (arithmetic mean) commission of exactly$150 on the 5 sales, then the average (arithmetic mean) of the final two sales must be

A. 60
B. 80
C. 115
D. 230
E. 280

$$250 + 95 + 175 + x + y = 150*5$$

Or, $$520 + ( x + y ) = 750$$

Or, ( x + y ) = $$230$$

So, Average from the 2 additional sales must be $$\frac{230}{2} = 115$$

Thus, answer will be (C) 115
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Re: On 3 sales Tom has received commissions of $250,$95, and $175, and ha [#permalink] ### Show Tags 28 Dec 2017, 03:33 Bunuel wrote: On 3 sales Tom has received commissions of$250, $95, and$175, and has two additional sales pending. If Tom is to receive an average (arithmetic mean) commission of exactly $150 on the 5 sales, then the average (arithmetic mean) of the final two sales must be A. 60 B. 80 C. 115 D. 230 E. 280 $$Average=\frac{Total.Sales}{Number.Sales}$$, and 2 more sales = $$2x$$ So $$150=\frac{(250+95+175+2x)}{5}$$, $$150(5)=(520+2x)$$, $$x=\frac{750-520}{2}=115$$ (C) is the answer. Re: On 3 sales Tom has received commissions of$250, $95, and$175, and ha &nbs [#permalink] 28 Dec 2017, 03:33
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