Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

On a class test there are 5 questions. One question has been [#permalink]

Show Tags

27 Mar 2013, 11:41

1

This post was BOOKMARKED

00:00

A

B

C

D

E

Difficulty:

75% (hard)

Question Stats:

46% (03:31) correct
54% (02:14) wrong based on 28 sessions

HideShow timer Statistics

On a class test there are 5 questions. One question has been taken from each of four chapters. The first two chapters have 3 questions each, the last two chapters have 6 questions each. The fourth question can be picked from any of the four chapters. How many different question papers could have been prepared?

Re: On a class test there are 5 questions. One question has been [#permalink]

Show Tags

27 Mar 2013, 13:50

1

This post received KUDOS

Are you sure of your answers?

I tried to figure it out but 4536 is my result, if some expert could help here... My way: number of ways to pick one from chapter I and II = 3C1 = 3 number of ways to pick one from chapter III and IV = 6C1 = 6 number of ways to pick one from the remaining 14 = 14C1 = 14 So my solution is 3*3*6*6*14=4536
_________________

It is beyond a doubt that all our knowledge that begins with experience.

Re: On a class test there are 5 questions. One question has been [#permalink]

Show Tags

29 Mar 2013, 14:24

Zarrolou wrote:

Are you sure of your answers?

I tried to figure it out but 4536 is my result, if some expert could help here... My way: number of ways to pick one from chapter I and II = 3C1 = 3 number of ways to pick one from chapter III and IV = 6C1 = 6 number of ways to pick one from the remaining 14 = 14C1 = 14 So my solution is 3*3*6*6*14=4536

+1 for 4536. please check and confirm the answer choices. thanks

Re: On a class test there are 5 questions. One question has been [#permalink]

Show Tags

15 Sep 2013, 01:07

I feel like 3.3.6.6.14 is not the right answer.

Imagine the first textbook has questions Q1, Q2, Q3. Now we can choose one of these, so it's a multiplier of 3. Let's say we picked Q1. Once we've finished picking the 4 questions and now it's time to pick the final question, imagine we pick from the first textbook. Since we already picked Q1, now we can only pick Q2 and Q3. This is a multiplier of 2. Let's imagine we picked Q2.

However, imagine another situation where we picked Q2 first, and then in the fifth round we can pick Q1 or Q3. It's still a multiplier of 2. Let's imagine we picked Q1.

However, picking Q1 first then Q2 later, or Q2 first and Q1 later, are the same combinations. But by using the 14- multipliers, we are not accounting for this.

Imagine the first textbook has questions Q1, Q2, Q3. Now we can choose one of these, so it's a multiplier of 3. Let's say we picked Q1. Once we've finished picking the 4 questions and now it's time to pick the final question, imagine we pick from the first textbook. Since we already picked Q1, now we can only pick Q2 and Q3. This is a multiplier of 2. Let's imagine we picked Q2.

However, imagine another situation where we picked Q2 first, and then in the fifth round we can pick Q1 or Q3. It's still a multiplier of 2. Let's imagine we picked Q1.

However, picking Q1 first then Q2 later, or Q2 first and Q1 later, are the same combinations. But by using the 14- multipliers, we are not accounting for this.

I think the OA is wrong as well...

That's correct.

On a class test there are 5 questions. One question has been taken from each of four chapters. The first two chapters have 3 questions each, the last two chapters have 6 questions each. The fourth question can be picked from any of the four chapters. How many different question papers could have been prepared? A. 540 B. 1260 C. 1080 D. 400 E. 4860

We can pick 2 questions from either of the four chapters.

If 2 questions are picked from the first chapter: \(C^2_3*3*6*6\);

If 2 questions are picked from the second chapter: \(3*C^2_3*6*6\);

If 2 questions are picked from the third chapter: \(3*3*C^2_6*6\);

If 2 questions are picked from the third chapter: \(3*3*6*C^2_6\).

Total = 2,268.

There is no correct answer among the options.
_________________

Re: On a class test there are 5 questions. One question has been [#permalink]

Show Tags

15 Sep 2013, 03:07

Bunuel wrote:

jubinell wrote:

I feel like 3.3.6.6.14 is not the right answer.

Imagine the first textbook has questions Q1, Q2, Q3. Now we can choose one of these, so it's a multiplier of 3. Let's say we picked Q1. Once we've finished picking the 4 questions and now it's time to pick the final question, imagine we pick from the first textbook. Since we already picked Q1, now we can only pick Q2 and Q3. This is a multiplier of 2. Let's imagine we picked Q2.

However, imagine another situation where we picked Q2 first, and then in the fifth round we can pick Q1 or Q3. It's still a multiplier of 2. Let's imagine we picked Q1.

However, picking Q1 first then Q2 later, or Q2 first and Q1 later, are the same combinations. But by using the 14- multipliers, we are not accounting for this.

I think the OA is wrong as well...

That's correct.

On a class test there are 5 questions. One question has been taken from each of four chapters. The first two chapters have 3 questions each, the last two chapters have 6 questions each. The fourth question can be picked from any of the four chapters. How many different question papers could have been prepared? A. 540 B. 1260 C. 1080 D. 400 E. 4860

We can pick 2 questions from either of the four chapters.

If 2 questions are picked from the first chapter: \(C^2_3*3*6*6\);

If 2 questions are picked from the second chapter: \(3*C^2_3*6*6\);

If 2 questions are picked from the third chapter: \(3*3*C^2_6*6\);

If 2 questions are picked from the third chapter: \(3*3*6*C^2_6\).

Total = 2,268.

There is no correct answer among the options.

Hi Bunuel,

I understood the way you have solved, but could you please help me understanding where I am going wrong.

Imagine the first textbook has questions Q1, Q2, Q3. Now we can choose one of these, so it's a multiplier of 3. Let's say we picked Q1. Once we've finished picking the 4 questions and now it's time to pick the final question, imagine we pick from the first textbook. Since we already picked Q1, now we can only pick Q2 and Q3. This is a multiplier of 2. Let's imagine we picked Q2.

However, imagine another situation where we picked Q2 first, and then in the fifth round we can pick Q1 or Q3. It's still a multiplier of 2. Let's imagine we picked Q1.

However, picking Q1 first then Q2 later, or Q2 first and Q1 later, are the same combinations. But by using the 14- multipliers, we are not accounting for this.

I think the OA is wrong as well...

That's correct.

On a class test there are 5 questions. One question has been taken from each of four chapters. The first two chapters have 3 questions each, the last two chapters have 6 questions each. The fourth question can be picked from any of the four chapters. How many different question papers could have been prepared? A. 540 B. 1260 C. 1080 D. 400 E. 4860

We can pick 2 questions from either of the four chapters.

If 2 questions are picked from the first chapter: \(C^2_3*3*6*6\);

If 2 questions are picked from the second chapter: \(3*C^2_3*6*6\);

If 2 questions are picked from the third chapter: \(3*3*C^2_6*6\);

If 2 questions are picked from the third chapter: \(3*3*6*C^2_6\).

Total = 2,268.

There is no correct answer among the options.

Hi Bunuel,

I understood the way you have solved, but could you please help me understanding where I am going wrong.

Or consider this. With your solution we can get: A1, B1, C1, D1, and then A2. But we can also get: A2, B1, C1, D1, and then A1, which is basically the same set.
_________________

Re: On a class test there are 5 questions. One question has been [#permalink]

Show Tags

15 Sep 2013, 11:00

shameekv wrote:

Bunuel wrote:

jubinell wrote:

I feel like 3.3.6.6.14 is not the right answer.

Imagine the first textbook has questions Q1, Q2, Q3. Now we can choose one of these, so it's a multiplier of 3. Let's say we picked Q1. Once we've finished picking the 4 questions and now it's time to pick the final question, imagine we pick from the first textbook. Since we already picked Q1, now we can only pick Q2 and Q3. This is a multiplier of 2. Let's imagine we picked Q2.

However, imagine another situation where we picked Q2 first, and then in the fifth round we can pick Q1 or Q3. It's still a multiplier of 2. Let's imagine we picked Q1.

However, picking Q1 first then Q2 later, or Q2 first and Q1 later, are the same combinations. But by using the 14- multipliers, we are not accounting for this.

I think the OA is wrong as well...

That's correct.

On a class test there are 5 questions. One question has been taken from each of four chapters. The first two chapters have 3 questions each, the last two chapters have 6 questions each. The fourth question can be picked from any of the four chapters. How many different question papers could have been prepared? A. 540 B. 1260 C. 1080 D. 400 E. 4860

We can pick 2 questions from either of the four chapters.

If 2 questions are picked from the first chapter: \(C^2_3*3*6*6\);

If 2 questions are picked from the second chapter: \(3*C^2_3*6*6\);

If 2 questions are picked from the third chapter: \(3*3*C^2_6*6\);

If 2 questions are picked from the third chapter: \(3*3*6*C^2_6\).

Total = 2,268.

There is no correct answer among the options.

Hi Bunuel,

I understood the way you have solved, but could you please help me understanding where I am going wrong.

14C1 is because we are left with 2+2+5+5 questions in each of the chapters respectively and that we have to chose the last one from those remaining.

When I solve this I get double of 2268 i.e. 4536...

Thanks in advance!!!

Hi, Well I am still in confusion..

What if the question had asked if there were 6 questions to be picked and last 2 can be picked from any of those questions remaining? And also if the last 2 can be picked only from one of the chapters.

Are we trying to divide the term 4536 by 2! since 2 questions represent same set from 1 chapter?

Could you please elaborate on this? I am trying to understand the concept here..

On a class test there are 5 questions. One question has been taken from each of four chapters. The first two chapters have 3 questions each, the last two chapters have 6 questions each. The fourth question can be picked from any of the four chapters. How many different question papers could have been prepared? A. 540 B. 1260 C. 1080 D. 400 E. 4860

We can pick 2 questions from either of the four chapters.

If 2 questions are picked from the first chapter: \(C^2_3*3*6*6\);

If 2 questions are picked from the second chapter: \(3*C^2_3*6*6\);

If 2 questions are picked from the third chapter: \(3*3*C^2_6*6\);

If 2 questions are picked from the third chapter: \(3*3*6*C^2_6\).

Total = 2,268.

There is no correct answer among the options.

Hi Bunuel,

I understood the way you have solved, but could you please help me understanding where I am going wrong.

14C1 is because we are left with 2+2+5+5 questions in each of the chapters respectively and that we have to chose the last one from those remaining.

When I solve this I get double of 2268 i.e. 4536...

Thanks in advance!!!

Hi, Well I am still in confusion..

What if the question had asked if there were 6 questions to be picked and last 2 can be picked from any of those questions remaining? And also if the last 2 can be picked only from one of the chapters.

Are we trying to divide the term 4536 by 2! since 2 questions represent same set from 1 chapter?

Could you please elaborate on this? I am trying to understand the concept here..

Campus visits play a crucial role in the MBA application process. It’s one thing to be passionate about one school but another to actually visit the campus, talk...

Its been long time coming. I have always been passionate about poetry. It’s my way of expressing my feelings and emotions. And i feel a person can convey...

Marty Cagan is founding partner of the Silicon Valley Product Group, a consulting firm that helps companies with their product strategy. Prior to that he held product roles at...

Written by Scottish historian Niall Ferguson , the book is subtitled “A Financial History of the World”. There is also a long documentary of the same name that the...