It is currently 14 Dec 2017, 16:59

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# On his birthday, Praet brings two pieces of cakes weighing

Author Message
Senior Manager
Joined: 21 Aug 2003
Posts: 257

Kudos [?]: 13 [0], given: 0

Location: Bangalore
On his birthday, Praet brings two pieces of cakes weighing [#permalink]

### Show Tags

22 Sep 2003, 03:13
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

On his birthday, Praet brings two pieces of cakes weighing 3/5 lbs & 7/20lbs. He wants to cut them into pieces of equal weights such that weight of each piece is maximum possible. Find the number of maximum guests praet could invite to his house. (assume: Praet will give atleast one cake to every guest).

Kudos [?]: 13 [0], given: 0

SVP
Joined: 03 Feb 2003
Posts: 1603

Kudos [?]: 312 [0], given: 0

### Show Tags

22 Sep 2003, 03:47
At the first glance: 3/5 and 7/20 are not terminating fractions
3/5=12/20
12/20 and 7/20 can be equally divided among 19 people.

19?

Kudos [?]: 312 [0], given: 0

Senior Manager
Joined: 21 Aug 2003
Posts: 257

Kudos [?]: 13 [0], given: 0

Location: Bangalore

### Show Tags

22 Sep 2003, 04:03
thats correct.
Now if two pieces are 6/5lbs & 9/10 lbs. What would be your answer?

Kudos [?]: 13 [0], given: 0

Senior Manager
Joined: 22 May 2003
Posts: 328

Kudos [?]: 176 [0], given: 0

Location: Uruguay

### Show Tags

22 Sep 2003, 16:38
Maybe 7? Each piece weighting 3/10 lbs

Kudos [?]: 176 [0], given: 0

Senior Manager
Joined: 21 Aug 2003
Posts: 257

Kudos [?]: 13 [0], given: 0

Location: Bangalore

### Show Tags

22 Sep 2003, 22:45
there u go.. yes it would be 7 each weighing 3/10 lbs.
we have to divide weights such that each has maximum possible weight.
21 will give each cake of weight 1/10lbs.

Kudos [?]: 13 [0], given: 0

Senior Manager
Joined: 02 Feb 2004
Posts: 344

Kudos [?]: 72 [0], given: 0

### Show Tags

21 May 2004, 11:52
can anybody show the workings better?

Kudos [?]: 72 [0], given: 0

SVP
Joined: 30 Oct 2003
Posts: 1788

Kudos [?]: 114 [0], given: 0

Location: NewJersey USA

### Show Tags

21 May 2004, 13:35
Assume that Praetorian divides 3/5 pound cake into n pieces and 7/20 pound cake into m pieces. m and n pieces have equal weight
Then
weight of each cake piece = (3/5)/n = 3/5n Since each cake piece has same weight
(3/5)/n = (7/20)/m
3/n = 7/4m therefore m = n * 7/12

Now we want minimum pieces because minimum pieces yeild maximum size and we know that m and n are integers
if n = 12 then m = 7
there fore praetorian will invite 7+12 = 19 guests.
I hope I am included

Kudos [?]: 114 [0], given: 0

21 May 2004, 13:35
Display posts from previous: Sort by

# On his birthday, Praet brings two pieces of cakes weighing

Moderator: chetan2u

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.