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# On July 1 of last year, total employees at company E was dec

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Senior Manager
Joined: 08 Jun 2004
Posts: 473
Location: Europe
On July 1 of last year, total employees at company E was dec  [#permalink]

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Updated on: 16 Sep 2013, 15:04
24
00:00

Difficulty:

35% (medium)

Question Stats:

76% (01:04) correct 24% (00:58) wrong based on 377 sessions

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On July 1 of last year, total employees at company E was decreased by 10 percent. Without any change in the salaries of the remaining employees, the average (arithmetic mean) employee salary was 10 percent more after the decrease in the number of employees than before the decrease. The total of the combined salaries of all the employees at Company E after July 1 last year was what percent of that before July 1 last year?

A. 90%
B. 99%
C. 100%
D. 101%
E. 110%

OPEN DISCUSSION OF THIS QUESTION IS HERE: on-july-1-of-last-year-total-employees-at-company-e-was-dec-85071.html

Originally posted by M8 on 04 Jul 2006, 02:18.
Last edited by Bunuel on 16 Sep 2013, 15:04, edited 1 time in total.
Edited the question and added the OA.
SVP
Joined: 30 Mar 2006
Posts: 1661

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04 Jul 2006, 02:36
2
1
B

Let the number of employess before Jul 1 be 100
Then Av sal1 = Total1/100

After Jul 1 employees = 90
Av Sal2 = Total2/90
Now from the question

Av2 = Av1 + 10%

Total2/90 = Total1/100 + 1/10 * Total1/100
Total2/90 = 11Total1/1000
Total2 = 99total1/100

Now Percent = Total2/Total1 * 100
= 99Total1/Total1
= 99
Manager
Joined: 19 Apr 2006
Posts: 228

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04 Jul 2006, 07:41
1
M8 wrote:
On July 1, of last year, the total number of employees at Company E was decreased by 10 percent. Wothout any change in the salaries of the remaining employees, the average (arithmetic mean) employee salary was 10 percent more after the decrease in number of employees than before the decrease. The total of the combined salaries of all of the employees at Company E after July 1 last year was what percent of that before July 1 last year?

1) 90
2) 99
3) 100
4) 101
5) 110

Sa = before July 1, A=mean
Sb = after July 1, B=mean

1. B = 1.10*A
2. (Sa/100) = A
3. (Sb/90) = B

Substitute above three equations to find Sb/Sa = 99
B
VP
Joined: 25 Nov 2004
Posts: 1427

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04 Jul 2006, 08:54
7
1
M8 wrote:
On July 1, of last year, the total number of employees at Company E was decreased by 10 percent. Wothout any change in the salaries of the remaining employees, the average (arithmetic mean) employee salary was 10 percent more after the decrease in number of employees than before the decrease. The total of the combined salaries of all of the employees at Company E after July 1 last year was what percent of that before July 1 last year?

1) 90
2) 99
3) 100
4) 101
5) 110

before
the total number of employees = n
the average salary = x
total salary to all emplyoees = xn

after
the total number of employees = n - 0.1n = 0.9n
the average salary = x + 10% of x = 1.1x
total salary to all emplyoees = 0.9n (1.1x)

total salary after as a % of total salary before = [0.9n (1.1x)]/xn= 0.99 or 99%
Intern
Joined: 23 Jun 2006
Posts: 23

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04 Jul 2006, 09:04
5
1
B.

Sustitute numbers -- 100 employees pre july 1 last year, \$100 per employee pre july 1 last year

Pre: (100 employees)*(100 salary) = 10,000 total salary
Post: (90 employees)*(110 salary) = 9,900 total salary

9900=(x/100)(10,000)
x = 99

99%
Math Expert
Joined: 02 Sep 2009
Posts: 52344
Re: On July 1 of last year, total employees at company E was dec  [#permalink]

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16 Sep 2013, 15:05
16
11
On July 1 of last year, total employees at company E was decreased by 10 percent. Without any change in the salaries of the remaining employees, the average (arithmetic mean) employee salary was 10 percent more after the decrease in the number of employees than before the decrease. The total of the combined salaries of all the employees at Company E after July 1 last year was what percent of that before July 1 last year?
A. 90%
B. 99%
C. 100%
D. 101%
E. 110%

# of employees before July 1 - $$x$$;
# of employees after July 1 - $$0.9x$$;

Average salary before July 1 - $$y$$;
Average salary after July 1 - $$1.1y$$;

Total salary before July 1 - $$xy$$;
Total salary after July 1 - $$1.1*0.9*xy=0.99xy$$ --> $$\frac{0.99xy}{xy}*100=99%$$.

OPEN DISCUSSION OF THIS QUESTION IS HERE: on-july-1-of-last-year-total-employees-at-company-e-was-dec-85071.html
_________________
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Joined: 09 Sep 2013
Posts: 9462
Re: On July 1 of last year, total employees at company E was dec  [#permalink]

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13 Jul 2018, 21:55
1
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Re: On July 1 of last year, total employees at company E was dec &nbs [#permalink] 13 Jul 2018, 21:55
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