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On July 1 of last year, total employees at company E was dec

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On July 1 of last year, total employees at company E was dec  [#permalink]

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New post 09 Oct 2009, 20:59
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On July 1 of last year, total employees at company E was decreased by 10 percent. Without any change in the salaries of the remaining employees, the average (arithmetic mean) employee salary was 10 percent more after the decrease in the number of employees than before the decrease. The total of the combined salaries of all the employees at Company E after July 1 last year was what percent of that before July 1 last year?

A. 90%
B. 99%
C. 100%
D. 101%
E. 110%
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Re: Ratios and Percents - Employee salaries  [#permalink]

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New post 09 Oct 2009, 22:06
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On July 1 of last year, total employees at company E was decreased by 10 percent. Without any change in the salaries of the remaining employees, the average (arithmetic mean) employee salary was 10 percent more after the decrease in the number of employees than before the decrease. The total of the combined salaries of all the employees at Company E after July 1 last year was what percent of that before July 1 last year?
A. 90%
B. 99%
C. 100%
D. 101%
E. 110%

# of employees before July 1 - \(x\);
# of employees after July 1 - \(0.9x\);

Average salary before July 1 - \(y\);
Average salary after July 1 - \(1.1y\);

Total salary before July 1 - \(xy\);
Total salary after July 1 - \(1.1*0.9*xy=0.99xy\) --> \(\frac{0.99xy}{xy}*100=99%\).

Answer B.
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Re: Ratios and Percents - Employee salaries  [#permalink]

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New post 19 May 2010, 20:26
Bunuel wrote:
On July 1 of last year, total employees at company E was decreased by 10%. Without any change in the salaries of the remaining employees, the average employee salary was 10% more after the decrease in the number of employees than before the decrease. The total of the combined salaries of all the employees at Company E after July 1 last year was what percent of that before July 1 of last year?

# of employees before July 1 - X
# of employees after July 1 - 0.9X

Average salary before July 1 - Y
Average salary after July 1 - 1.1Y

Total salary before July 1 - XY
Total salary after July 1 - 1.1*0.9*XY=0.99XY --> (1.1*0.9*XY)/XY*100=99%

Answer B.


Bunuel, I would disagree with you here ....the question said that there was no decrease in the salary of other employees but you wrote 1.1Y ...shouldnt it still be Y after the change ?
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Re: Ratios and Percents - Employee salaries  [#permalink]

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New post 20 May 2010, 02:29
dimitri92 wrote:
Bunuel wrote:
On July 1 of last year, total employees at company E was decreased by 10%. Without any change in the salaries of the remaining employees, the average employee salary was 10% more after the decrease in the number of employees than before the decrease. The total of the combined salaries of all the employees at Company E after July 1 last year was what percent of that before July 1 of last year?

# of employees before July 1 - X
# of employees after July 1 - 0.9X

Average salary before July 1 - Y
Average salary after July 1 - 1.1Y

Total salary before July 1 - XY
Total salary after July 1 - 1.1*0.9*XY=0.99XY --> (1.1*0.9*XY)/XY*100=99%

Answer B.


Bunuel, I would disagree with you here ....the question said that there was no decrease in the salary of other employees but you wrote 1.1Y ...shouldnt it still be Y after the change ?


"the average employee salary was 10% more after the decrease in the number of employees than before the decrease."
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Re: Question Help  [#permalink]

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New post 07 Dec 2010, 19:01
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dc123 wrote:
On july 1st of last year, the total number of employees at company E was decreased by 10%. Without any change in the salaries of the remaining employees, the avg employee salary was 10% more after the decrease in number of employees that before the decrease. The total combine salaries of all the employees at company E after July 1 last year was what percent of the before july 1 of last year?

90%

99%

100%

101%

110%

Help plz....


Question with percentages and answer also in percentages. The first and only thing I want to do is assume values.

Initial total no of emp = 100 (assumed value)
Initial total salary = 100 (assumed value)
Initial average = $1/emp (100/100 = 1)
New total no of emp = 90 (10% decrease)
New average salary = $1.1/emp (10% increase)
New total salary = 90*1.1 = 99
So new total salary is 99% of initial total salary.
Answer (B)
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Re: On July 1 of last year, total employees at company E was dec  [#permalink]

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New post 26 Oct 2013, 02:40
shanewyatt wrote:
On July 1 of last year, total employees at company E was decreased by 10 percent. Without any change in the salaries of the remaining employees, the average (arithmetic mean) employee salary was 10 percent more after the decrease in the number of employees than before the decrease. The total of the combined salaries of all the employees at Company E after July 1 last year was what percent of that before July 1 last year?

A. 90%
B. 99%
C. 100%
D. 101%
E. 110%



TotalSalarynew = Empnew X AverageSalnew
TotalSalarynew = 9/10 Empold X 11/10 AverageSalold
TotalSalarynew = 99/100 TotalSalaryold
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Re: On July 1 of last year, total employees at company E was dec  [#permalink]

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New post 28 Sep 2015, 08:21
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shanewyatt wrote:
On July 1 of last year, total employees at company E was decreased by 10 percent. Without any change in the salaries of the remaining employees, the average (arithmetic mean) employee salary was 10 percent more after the decrease in the number of employees than before the decrease. The total of the combined salaries of all the employees at Company E after July 1 last year was what percent of that before July 1 last year?

A. 90%
B. 99%
C. 100%
D. 101%
E. 110%

Choose some nice values that satisfy the given information.

BEFORE July 1
Let's say that there were 10 employees
And let's say the average salary was $10.
TOTAL payroll = (10)($10) =$100

Number of employees decreases by 10%
Average salary increases by 10%
So....

AFTER July 1
There are 9 employees
Average salary is $11.
TOTAL payroll = (9)($11) =$99

The total of the combined salaries of all the employees at Company E after July 1 last year was what percent of that before July 1 last year?

99/100 = [spoiler]99%[/spoiler]

Answer: B
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Re: On July 1 of last year, total employees at company E was dec  [#permalink]

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New post 28 Sep 2015, 21:47
1
NicolasMerigo93 wrote:
On July 1 of last year, the total number of employees at Company E was decreased by 10 percent. Without any change in the salaries of the remaining employees, the average(arithmetic mean) employee salary was 10 percent more after the decrease in number of employees than before the decrease. The total of the combined salaries of all of the employees at Company E after July 1 last year was what percent of that before July 1 last year?

(A) 90%

(B) 99%

(C) 100%

(D) 101%

(E) 110%


If we try to solve this question by assuming values, it becomes fairly easy.

Let initial total employees on July 1= 100
Let the initial salary = $100
Average = $1


New number of employees after 10% decrease = 90
New average salary after 10% increase= $1.1

New salary = 90*1.1 = 99
Which is 99% of the initial salary

Correct choice: B
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Re: On July 1 of last year, total employees at company E was dec  [#permalink]

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New post 29 Oct 2016, 02:46
shanewyatt wrote:
On July 1 of last year, total employees at company E was decreased by 10 percent. Without any change in the salaries of the remaining employees, the average (arithmetic mean) employee salary was 10 percent more after the decrease in the number of employees than before the decrease. The total of the combined salaries of all the employees at Company E after July 1 last year was what percent of that before July 1 last year?

A. 90%
B. 99%
C. 100%
D. 101%
E. 110%


Draw a chart -
Attachment:
Capture.PNG
Capture.PNG [ 5.22 KiB | Viewed 2488 times ]


The answer will clearly be \(\frac{9900}{10000}*100 =\) \(99\)%

Hence answer will be (B)
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On July 1 of last year, total employees at company E was dec  [#permalink]

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New post 12 Oct 2018, 05:29
Number of employee (before= X) (after= 0.9X)
Total Salary (before= Sb) (after= Sa)

Average Salary (before =Sb/X)
Average Salary (after = Sa/0.9X)

Average Salary is increased 10%
So, 1.1*Sb/X =Sa/0.9X
Now, 0.99Sb=Sa
Therefore, Sb is 99% of Sa

Answer=99%
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On July 1 of last year, total employees at company E was dec &nbs [#permalink] 12 Oct 2018, 05:29
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