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when find diffrence is just 2*3^11, u can set up simple equation: 3^12 - X * 2* 3^11 = -(3^12) so x times the difference should get us to our goal -X *2* 3^11 = -(3^12) - (3^12) -X *2* 3^11 = -2*3 (3^12) minus 2 cancel out and only thing we lack for this is x to be 3 so that it makes 3^12 Count 3 marks from it and we arrive at D
On the number line shown, the tick marks are equally spaced and the coordinates of points F and G are 3^11 and 3^12, respectively. Which of the following points has the coordinate -(3^12) ?
How it made sense to me : 3^12 - 3^11 = 3^11(3-1) = (3^11)(2) --> this is the space between each tick if you go one space back (e) you have 3^11 - 1(3^11)(2) = -3^11 if you go TWO spaces back (d) you get 3^11 - 2 (3^11)(2) = 3^11 -4(3^11) = -3^11 (4-1) = -3^11(3) = -3^12 (minus because we are going backwards, if we had to find a higher up tick it would be +) Godspeed
The difference between F and G is 3^12-3^11, which can be factored into 3^11(3-1) = 3^11(2) F=3^11 E=F-3^11(2) E= -3^11 D=E-(-3^11) D=-3^12
Bunuel
On the number line shown, the tick marks are equally spaced and the coordinates of points F and G are 3^11 and 3^12, respectively. Which of the following points has the coordinate -(3^12) ?