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11 Dec 2016, 05:39
Kudos
Bookmarks
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
79% (01:49) correct
21%
(02:29)
wrong
based on 226
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On the table, there are 10 mathematics books and 5 literature books. Jane takes one randomly, then Anna takes one book randomly. Finally, John takes one of remaining on the table. What is the probability that Jane and Anna take mathematics books and John takes literature books?
A. 18/91
B. 15/91
C. 7/45
D. 8/15
E. 45/91
A. 18/91
B. 15/91
C. 7/45
D. 8/15
E. 45/91
11 Dec 2016, 09:09
Kudos
Bookmarks
Hi
Thanks for posting new questions.
\(P(math)*P(math)|math*P(lit)|math,math = \frac{10}{15} * \frac{9}{14} * \frac{5}{13} = \frac{15}{91}\)
Answer B.
Thanks for posting new questions.
\(P(math)*P(math)|math*P(lit)|math,math = \frac{10}{15} * \frac{9}{14} * \frac{5}{13} = \frac{15}{91}\)
Answer B.
11 Dec 2016, 12:13
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nguyendinhtuong
On the table, there are 10 mathematics books and 5 literature books. Jane takes one randomly, then Anna takes one book randomly. Finally, John takes one of remaining on the table. What is the probability that Jane and Anna take mathematics books and John takes literature books?
A. 18/91
B. 15/91
C. 7/45
D. 8/15
E. 45/91
A. 18/91
B. 15/91
C. 7/45
D. 8/15
E. 45/91
Probability that Jane takes out a mathematics book = \(\frac{10}{15}\)
Probability that Anna takes out a mathematics book = \(\frac{9}{14}\)
Probability that John takes out a mathematics book = \(\frac{5}{13}\)
So, the probability that Jane and Anna take mathematics books and John takes literature books is \(\frac{10}{15}\)*\(\frac{9}{14}\)*\(\frac{5}{13}\) = \(\frac{15}{91}\)
Hence, answer will be (B)
