|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
28 Mar 2019, 05:57
Kudos
Bookmarks
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
83% (01:54) correct
17%
(01:46)
wrong
based on 66
sessions
History
Date
Time
Result
Not Attempted Yet
One dimension of a cube is increased by 1, another is decreased by 1, and the third is left unchanged. The volume of the new rectangular solid is 5 less than that of the cube. What was the volume of the cube?
(A) 8
(B) 27
(C) 64
(D) 125
(E) 216
(A) 8
(B) 27
(C) 64
(D) 125
(E) 216
28 Mar 2019, 09:06
Kudos
Bookmarks
Let a be the side of the cube. The volume of the cube \(a^3\)
After adjustment the new figure has the volume: (a-1)(a+1)(a)=\(a^3\)-a
According to the stem: \(a^3\)-(\(a^3\)-a)=5
a=5
The volume of the initial cube is 125
Imo
Ans: D
After adjustment the new figure has the volume: (a-1)(a+1)(a)=\(a^3\)-a
According to the stem: \(a^3\)-(\(a^3\)-a)=5
a=5
The volume of the initial cube is 125
Imo
Ans: D
31 Mar 2019, 11:47
Kudos
Bookmarks
Bunuel
We can create the equation:
n^3 = (n + 1)(n - 1)n + 5
n^3 = (n^2 - 1)n + 5
n^3 = n^3 - n + 5
n = 5
So the volume of the original cube was 5^3 = 125.
Answer: D
