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# One-kth of a circular pie has been served. If the rest of the pie is

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Math Expert
Joined: 02 Sep 2009
Posts: 59587
One-kth of a circular pie has been served. If the rest of the pie is  [#permalink]

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11 Mar 2019, 01:54
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2
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Difficulty:

35% (medium)

Question Stats:

69% (01:36) correct 31% (01:42) wrong based on 55 sessions

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One-k th of a circular pie has been served. If the rest of the pie is divided into n equal servings, then each of these servings is what fraction of the whole pie?

A. 1/(nk)
B. (k - n)/(kn)
C. 1/(n - k)
D. (k - 1)/(nk)
E. (k - 1)/n

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GMAT Club Legend
Joined: 18 Aug 2017
Posts: 5428
Location: India
Concentration: Sustainability, Marketing
GPA: 4
WE: Marketing (Energy and Utilities)
Re: One-kth of a circular pie has been served. If the rest of the pie is  [#permalink]

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11 Mar 2019, 05:34
Bunuel wrote:
One-k th of a circular pie has been served. If the rest of the pie is divided into n equal servings, then each of these servings is what fraction of the whole pie?

A. 1/(nk)
B. (k - n)/(kn)
C. 1/(n - k)
D. (k - 1)/(nk)
E. (k - 1)/n

cake = 1
served = 1/k
left
1-1/k
k-1/k
n equal servings
k-1/kn
IMO D
Intern
Joined: 18 Jan 2019
Posts: 28
Re: One-kth of a circular pie has been served. If the rest of the pie is  [#permalink]

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06 Apr 2019, 09:44
Archit3110 wrote:
Bunuel wrote:
One-k th of a circular pie has been served. If the rest of the pie is divided into n equal servings, then each of these servings is what fraction of the whole pie?

A. 1/(nk)
B. (k - n)/(kn)
C. 1/(n - k)
D. (k - 1)/(nk)
E. (k - 1)/n

cake = 1
served = 1/k
left
1-1/k
k-1/k
n equal servings
k-1/kn
IMO D

can you explain what you did with the n? What's the logic behind that?
GMAT Club Legend
Joined: 18 Aug 2017
Posts: 5428
Location: India
Concentration: Sustainability, Marketing
GPA: 4
WE: Marketing (Energy and Utilities)
Re: One-kth of a circular pie has been served. If the rest of the pie is  [#permalink]

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07 Apr 2019, 00:42
1
Ish1996 wrote:
Archit3110 wrote:
Bunuel wrote:
One-k th of a circular pie has been served. If the rest of the pie is divided into n equal servings, then each of these servings is what fraction of the whole pie?

A. 1/(nk)
B. (k - n)/(kn)
C. 1/(n - k)
D. (k - 1)/(nk)
E. (k - 1)/n

cake = 1
served = 1/k
left
1-1/k
k-1/k
n equal servings
k-1/kn
IMO D

can you explain what you did with the n? What's the logic behind that?

Ish1996
solution as follows:

let value of cake be 1
total cake which was served = 1/k
so we are now left with = 1-1/k = k-1/k

this left over cake is now to be served equally in n servings ; i.e we need to divide the left over cake value by 'n'

so each of n equal servings
k-1/kn

the above value will be fraction value of whole cake value viz. 1 ..

hope this helps.
IMO D
Re: One-kth of a circular pie has been served. If the rest of the pie is   [#permalink] 07 Apr 2019, 00:42
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