Anki111
One side of a triangle has length 8 and a second side has length 5. Which of the following could be the area of the triangle?
I. 24
II. 20
III. 5
A. I only
B. II only
C. III only
D. II and III only
E. I, II and III
If the minimum length of the third side could be 4 then the minimum area is 1/2*4*5=10 which rules out the possibility of getting III. Could you explain, how can we derive that the lowest area it can go is zero?
Thanks in advance.
The length of any side of a triangle must be larger than the positive difference of the other two sides, but smaller than the sum of the other two sides.
Thus, if the lengths of the two sides of a triangle are 5 and 8, then (8 - 5) < third side < (8 + 5). Hence, the length of the third side is between 3 and 13, not inclusive. This, however, does not mean that the minimum length of the third side is 4, as we are not told that the lengths of the sides must be integers.
Next, the area of a triangle with the sides of 4, 5, and 8 is not 1/2*4*5=10, it's \(\frac{3\sqrt {119} }{4}≈8.18...\). The area of a triangle is 1/2*base*height, and since a (4, 5, 8) triangle is not right-angled, its area is not 1/2*4*5 = 10 (the sides with lengths of 4 and 5 are not perpendicular to each other, so they cannot be considered as the height and base).
Finally, when the angle between the sides with the lengths of 5 and 8 approaches 0, the area of the triangle also approaches 0. By adjusting the angle, you can get any area from 0 to 20. (We achieve a maximum area of 20 when the angle between the sides measuring 5 and 8 is 90 degrees. This is because the area, computed using the formula 1/2 * base * height, is maximized when the side measuring 8 is considered the base and the height is maximized. Upon visualizing this, it becomes evident that the height is maximized when it is also equal to the other side of 5.)
Hope it's clear.