Bunuel wrote:

One-tenth of the employees at a company dinner are vice-presidents, and one-third of the remaining employees are assistant vice-presidents. If there are e employees in attendance, how many employees in attendance are neither vice-presidents nor assistant vice-presidents?

A. e/30

B. 2e/5

C. 13e/30

D. 17e/30

E. 3e/5

One approach is to use the INPUT-OUTPUT approach (described in our free video -

http://www.gmatprepnow.com/module/gmat- ... /video/933)

We have two fractions (1/10 and 1/3), so let's let e = the least common denominator of these two fraction.

We'll let

e = 30If there are 30 employees, then the number of vice-presidents = (1/10)(30) = 3

one-third of the remaining employees are assistant vice-presidentsThere are 27 employees remaining.

1/3 of 27 = 9, so there are 9 assistant vice-presidents

So, the total number of vice-presidents AND assistant vice-presidents = 3 + 9 = 12

So, the number of employees who are NEITHER vice-presidents nor assistant vice-presidents = 30 - 12 =

18So, when the INPUT

e = 30, the OUTPUT is

18 people who are NEITHER vice-presidents nor assistant vice-president

Now check the answer choices to see which one yields an OUTPUT of

18, when we INPUT

e = 30A. e/30 =

30/30 =

1 - NO - ELIMINATE

B. 2e/5 = 2(

30)/5 =

12 - NO - ELIMINATE

C. 13e/30 = 13(

30)/30 =

13 - NO - ELIMINATE

D. 17e/30 = 17(

30)/30 =

17 - NO - ELIMINATE

E. 3e/5 = 3(

30)/5 =

18 - YES - KEEP

Answer: E

Cheers,

Brent

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