Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Jun 0210:00 AM PDT
-11:00 AM PDT
Probability is one of the most important GMAT Quant topics because it often combines logic, counting, set theory, and permutations & combinations. Many students try to solve probability questions by listing every possible case, but GMAT probability...
May 2110:00 AM EDT
-11:59 PM EDT
Make the most of your break with the most realistic GMAT™ prep. Take up to $700 off select products.
May 2910:00 AM IST
-11:00 PM IST
Start your journey with a fully customized action plan and work with a dedicated mentor to achieve a 735+ score.- Jun 10
06:00 AM PDT
-06:15 PM PDT
Register for the GMAT Club Virtual MBA Spotlight Fair – the world’s premier event for serious MBA candidates. This is your chance to hear directly from Admissions Directors at nearly every Top 30 MBA program..
Hello, everyone,
Please give me an advice, how this modification in divisor (between steps 2 and 3) is possible (an attachment is also available)?
How is it possible to multiply an expression in the divisor by (-1) and change the order of units?
What mathematical rule does govern it?
\(\frac{x+1}{1-x}= \frac{x+1}{-(1-x)} = \frac{x+1}{x-1}\)
Many thanks in advance!
Please give me an advice, how this modification in divisor (between steps 2 and 3) is possible (an attachment is also available)?
How is it possible to multiply an expression in the divisor by (-1) and change the order of units?
What mathematical rule does govern it?
\(\frac{x+1}{1-x}= \frac{x+1}{-(1-x)} = \frac{x+1}{x-1}\)
Many thanks in advance!
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block below for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
17 Dec 2011, 16:36
Kudos
Bookmarks
marus
I'm not quite sure I understand your question, but the equation above isn't right. The first fraction is not equal to the second - in fact, it's exactly equal to the negative of the second. The second and third fractions are equal.
marus
There is no 'order' when you're adding numbers; a+b is the same thing as b+a. By the same token, x-1 is the same thing as -1+x. If we want, we can factor out -1; when we do, we'll need to 'flip' all of the signs in the brackets. So -(1 - x) is equal to -1 + x, as you can confirm by expanding -(1 - x). So the following four expressions are all equal:
\(x - 1 = -1 + x = -(1 - x) = -(-x + 1)\)
18 Dec 2011, 14:25
Kudos
Bookmarks
Many thanks for the reply, it was useful for me and now I understand why this multiplication was done with the expression inside an absolute value parentheses!
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
