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03 Jun 2025, 00:30
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
57% (02:18) correct
43%
(02:02)
wrong
based on 109
sessions
History
Date
Time
Result
Not Attempted Yet
Over the course of a year, a certain house appreciated in value by 10 percent while the house next door decreased in value by 10 percent as a result of foundation damage. At the end of the year, the reduced price of the second house was what percentage of the increased price of the first house?
(1) The amount by which the first house increased in value was half as much as the amount by which the second house decreased in value.
(2) At the end of the year, the second house was worth $70,000 more than the first house.
Gentle note to all experts and tutors: Please refrain from replying to this question until the Official Answer (OA) is revealed. Let students attempt to solve it first. You are all welcome to contribute posts after the OA is posted. Thank you all for your cooperation!
(1) The amount by which the first house increased in value was half as much as the amount by which the second house decreased in value.
(2) At the end of the year, the second house was worth $70,000 more than the first house.
Gentle note to all experts and tutors: Please refrain from replying to this question until the Official Answer (OA) is revealed. Let students attempt to solve it first. You are all welcome to contribute posts after the OA is posted. Thank you all for your cooperation!
Updated on: 03 Jun 2025, 11:19
Originally posted by ManifestDreamMBA on 03 Jun 2025, 10:41.
Last edited by ManifestDreamMBA on 03 Jun 2025, 11:19, edited 1 time in total.
Last edited by ManifestDreamMBA on 03 Jun 2025, 11:19, edited 1 time in total.
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Let the price of the houses be x and y
H1 price = 1.1x
H2 price = 0.9y
0.9y/1.1x = ?
Need y/x or x/y
S1
0.1x = 0.5 * 0.1y
2x=y
x/y = 1/2
Sufficient
S2
0.9y - 1.1x = 70000
We don't know x/y
Insufficient
Answer A
H1 price = 1.1x
H2 price = 0.9y
0.9y/1.1x = ?
Need y/x or x/y
S1
0.1x = 0.5 * 0.1y
2x=y
x/y = 1/2
Sufficient
S2
0.9y - 1.1x = 70000
We don't know x/y
Insufficient
Answer A
Bunuel
Over the course of a year, a certain house appreciated in value by 10 percent while the house next door decreased in value by 10 percent as a result of foundation damage. At the end of the year, the reduced price of the second house was what percentage of the increased price of the first house?
(1) The amount by which the first house increased in value was half as much as the amount by which the second house decreased in value.
(2) At the end of the year, the second house was worth $70,000 more than the first house.
Gentle note to all experts and tutors: Please refrain from replying to this question until the Official Answer (OA) is revealed. Let students attempt to solve it first. You are all welcome to contribute posts after the OA is posted. Thank you all for your cooperation!
(1) The amount by which the first house increased in value was half as much as the amount by which the second house decreased in value.
(2) At the end of the year, the second house was worth $70,000 more than the first house.
Gentle note to all experts and tutors: Please refrain from replying to this question until the Official Answer (OA) is revealed. Let students attempt to solve it first. You are all welcome to contribute posts after the OA is posted. Thank you all for your cooperation!
03 Jun 2025, 11:00
Kudos
Bookmarks
Bunuel
Over the course of a year, a certain house appreciated in value by 10 percent while the house next door decreased in value by 10 percent as a result of foundation damage. At the end of the year, the reduced price of the second house was what percentage of the increased price of the first house?
(1) The amount by which the first house increased in value was half as much as the amount by which the second house decreased in value.
(2) At the end of the year, the second house was worth $70,000 more than the first house.
Gentle note to all experts and tutors: Please refrain from replying to this question until the Official Answer (OA) is revealed. Let students attempt to solve it first. You are all welcome to contribute posts after the OA is posted. Thank you all for your cooperation!
Let the price of the first house be P1, and the price of Second House be P2. (1) The amount by which the first house increased in value was half as much as the amount by which the second house decreased in value.
(2) At the end of the year, the second house was worth $70,000 more than the first house.
Gentle note to all experts and tutors: Please refrain from replying to this question until the Official Answer (OA) is revealed. Let students attempt to solve it first. You are all welcome to contribute posts after the OA is posted. Thank you all for your cooperation!
The price of house 1 appreciates by 10% = P1* 11/10
The price of house 2 depreciates by 10% = P2* 9/10
We need to find : (9 *P2)/10 = x% of (11* P1)/10
hence, x % = ( 9 P2/ 11 P1) .
Statement 1:
(1) The amount by which the first house increased in value was half as much as the amount by which the second house decreased in value.
(P1/10) = (1/2)* (P2/10)
P1/ P2 = 1/2
P1 : P2 = 1:2
Substituting in x% = ( 9 P2/ 11 P1) . , we get
x% = (9*2)/11 = 1.636. Which is a 163.6 % increase.
Thus, Statement 1 is sufficent.
Statement 2:
(2) At the end of the year, the second house was worth $70,000 more than the first house.
(9*P2)/10 = $70000 + (11*P1)/10
This equation is not sufficient to find x% .
Hence, Insufficient
Option A
