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30 May 2010, 05:54
Kudos
Bookmarks
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
75% (01:26) correct
25%
(01:42)
wrong
based on 815
sessions
History
Date
Time
Result
Not Attempted Yet
\(\frac{p+5+p^3(-p-5)}{-p-5}=\)
A. p+5+p^3
B. P^3+5
C. p^3
D. p^3-1
E. p^3-5
A. p+5+p^3
B. P^3+5
C. p^3
D. p^3-1
E. p^3-5
30 May 2010, 06:49
Kudos
Bookmarks
\(\frac{p+5+p^3(-p-5)}{-p-5}=\)
A. p+5+p^3
B. P^3+5
C. p^3
D. p^3-1
E. p^3-5
\(\frac{p+5+p^3(-p-5)}{-p-5}=\frac{-(-p-5)+p^3(-p-5)}{-p-5}\);
Factor out \((-p-5)\):
\(\frac{-(-p-5)+p^3(-p-5)}{-p-5}=\frac{(-p-5)(-1+p^3)}{-p-5}=-1+p^3=p^3-1\).
Answer: D.
Hope it helps.
A. p+5+p^3
B. P^3+5
C. p^3
D. p^3-1
E. p^3-5
\(\frac{p+5+p^3(-p-5)}{-p-5}=\frac{-(-p-5)+p^3(-p-5)}{-p-5}\);
Factor out \((-p-5)\):
\(\frac{-(-p-5)+p^3(-p-5)}{-p-5}=\frac{(-p-5)(-1+p^3)}{-p-5}=-1+p^3=p^3-1\).
Answer: D.
Hope it helps.
30 Nov 2017, 11:19
Kudos
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undernet
We're looking for an expression that is equivalent to the original expression.
So if we evaluate the original expression for a particular value of p, then the equivalent expression should also yield the same value when we plug in the same value of p.
Let's test p = 1
Take: [p + 5 + p³(-p - 5)]/[-p - 5]
Replace p with 1 to get: [1 + 5 + 1³(-1 - 5)]/[-1 - 5]
Evaluate to get: 0/-6, which equals 0
So, when p = 1, the original express evaluates to be 0
Now let's plug p = 1 into the answer choices....
A. 1 + 5 + 1^3 = 7. No good, we want 0. ELIMINATE.
B. 1^3 + 5 = 6. No good, we want 0. ELIMINATE.
C. 1^3 = 1. No good, we want 0. ELIMINATE.
D. 1^3 - 1 = 0. Great - KEEP
E. 1^3 - 5 = -4. No good, we want 0. ELIMINATE.
Answer: D
Cheers,
Brent
