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P, Q, and R are nonzero integers. Is P/(Q*R) an integer? (1)

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SVP
Joined: 03 Feb 2003
Posts: 1604
P, Q, and R are nonzero integers. Is P/(Q*R) an integer? (1) [#permalink]

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29 May 2003, 03:30
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

P, Q, and R are nonzero integers. Is P/(Q*R) an integer?

(1) P/Q=3
(2) P/R=2
SVP
Joined: 03 Feb 2003
Posts: 1604

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29 May 2003, 03:58
Try to pick numbers

P=6, Q=2, R=3
P=12, Q=4, R=6
Manager
Joined: 28 Feb 2003
Posts: 100

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29 May 2003, 05:15
SVP
Joined: 03 Feb 2003
Posts: 1604

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29 May 2003, 05:32
You have been so lucky with my problems for so long that I have to create something more difficult.
Manager
Joined: 28 Feb 2003
Posts: 100

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29 May 2003, 05:44
yes.....really good questions.....

i am feeling a bit down now.......don't know maybe i am losing my tempo after registering for the exam.

hope to catch up in sometime
Senior Manager
Joined: 03 Nov 2005
Posts: 384
Location: Chicago, IL

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21 Nov 2005, 21:18
I believe the answer to this one is E. We can write the expression P/(Q*R) as P/Q*1/R or P/R*1/Q

(1) we can substitute P/Q=3 Then the expression becomes 3*1/R. picking different values for R. if R=2, then the expression 3*1/2=3/2 a non-integer. However, if R=1 then 3*1/1=3 is an integer. therefore, (1) is insifficient.

(2)Again P/(Q*R)=P/Q*1/R. If P/Q=2 then we should pick different numbers for 2*1/R. if R=2, 2*1/2=1 which is an integer. However if R=3, 2*1/3=2/3 is not So, (2) is insufficient.

Combining statements. If pick values P=6, Q=2, R=3 6/2*3=1 integer but for values P=12, Q=4, R=6, 12/4*6=1/2 non-integer. So both statements together are insufficient. the answer is E.
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21 Nov 2005, 21:18
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