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26 Jan 2021, 11:52
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C
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If k is a constant, then the equations kx + y = 3 and 4x + ky = 4 will have a unique solution if and only if the value of k is?
A. |k| = 2
B. k ≠ 2
C. |k| ≠ 2
D. k = 2
E. k = 0
A. |k| = 2
B. k ≠ 2
C. |k| ≠ 2
D. k = 2
E. k = 0
26 Jan 2021, 23:31
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For any 2 equations of the for a1x + b1y = c1 and a2x + b2y = c2, we get a unique solution when \(\frac{a_1}{a_2} \neq \frac{b_1}{b_2}\)
Therefore in the system of equations given, we get a unique solution when \(\frac{k}{4} \neq \frac{1}{k}\)
Solving, we get \(k^2 \neq 4\), or \(k \neq \pm 2\) which is the same as |k| \(\neq\) 2
Option C
Arun Kumar
Therefore in the system of equations given, we get a unique solution when \(\frac{k}{4} \neq \frac{1}{k}\)
Solving, we get \(k^2 \neq 4\), or \(k \neq \pm 2\) which is the same as |k| \(\neq\) 2
Option C
Arun Kumar
General Discussion
30 Nov 2023, 08:01
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