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Percent problem

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Intern
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Joined: 28 Jun 2008
Posts: 45

Kudos [?]: 135 [0], given: 31

Percent problem [#permalink]

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New post 13 Jun 2009, 11:11
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Hi guys was wondering if anyone could offer a good way to solve this problem:

In May Mrs. Lee's earnings were 60 percent of the Lee's total family income. In June Mrs. Lee earned 20 percent more than in May. If the rest of the family's income was the same in both months , then, in June, Mrs. Lee's earnings were approximately what percent of the Lee family's total income?

A. 64 %
B. 69%
C. 72%
D. 76%
E. 80%

Answer: A.

Kudos [?]: 135 [0], given: 31

Current Student
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Joined: 13 Jan 2009
Posts: 364

Kudos [?]: 144 [0], given: 1

Location: India
Re: Percent problem [#permalink]

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New post 12 Jul 2009, 12:29
Let family income be x.
So Mary's income is .6x

After raise Mary's income .72x

% of Mary's income=.72x/(x+.72x-.6x)
This will give nearly 64%

Kudos [?]: 144 [0], given: 1

Senior Manager
Senior Manager
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Joined: 04 Jun 2008
Posts: 286

Kudos [?]: 155 [0], given: 15

Re: Percent problem [#permalink]

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New post 12 Jul 2009, 16:57
hemantsood wrote:
Let family income be x.
So Mary's income is .6x

After raise Mary's income .72x

% of Mary's income=.72x/(x+.72x-.6x)
This will give nearly 64%


This is the shortest way to solve, but instead of taking x, it is always better to use 100%

ie, just like you take total to be x, take it to be 100. Calculations can be done far more easily, even mentally with integers.

for eg: total family income = 100
mary's income = 60
income after 20% increase = 60 *1.2 = 72
family's new income = 112

new %age = 72/112

Kudos [?]: 155 [0], given: 15

Re: Percent problem   [#permalink] 12 Jul 2009, 16:57
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