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Senior Manager
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New post 13 Jul 2004, 09:24
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Perhaps, i wud have asked this question before, tried for a search, cud not get it, Hence I post it here.

In a group of people, there are 50% of men who are below age 40. And 40% of the females are below 40.. If the total people below the age below 40 are 42% of the people, Then how many percent of females are there in total.

please explain answers
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New post 13 Jul 2004, 09:41
M - Number of Men.
W - Number of Women.

1 ) M+W = 100. (100%... Easier to work with a number)

42% - are people under 40.

2) 0.5M + 0.4W = 42.

Solving those two equations i got W= 80.

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New post 13 Jul 2004, 09:59
I agree with Dookie - it's 80%. I have a non-algebra approach that works for this exact problem.

Draw a quick diagram putting all the percentages together that looks like this:

40------42-----------50
W_____t_________M


Then see what the differences are between all the numbers and the middle:

40------42-----------50
W__2__t_____8___M


Now make a ratio using the opposite differences:

w:m = 8:2

so w:whole = 8:10 = 80%

It looks like a lot when it's typed out like this, but see the attachment for how simple it is:
Image

This works for every question where they give you the percentage of two distinct groups, and then the combined percentage as well.

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New post 13 Jul 2004, 10:02
Dookie, can u explain a little in detail, please.

Thanks bro.
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New post 13 Jul 2004, 12:19
0.5M + 0.4F =0.42(M+F)

solve

F/M = 8/2. Hence 80%

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New post 13 Jul 2004, 21:05
m > men
w > women
t > total

m + w = t
50/100 * m + 40/100 * w = 42/100 * t

This results in w/t = 4/5 ..which equals %80

Hope this is clear!


:fyi

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New post 16 Jul 2004, 08:06
Ian, i am unable to see any attachements. Can u please resend them?.

Thanks mate.
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New post 16 Jul 2004, 08:28
80 percent


m + f = 100
0.5m + o.4f = 42

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  [#permalink] 16 Jul 2004, 08:28
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