Bunuel wrote:
Peter invests a sum of money and gets back an amount of $815 in 3 years. David invests an equal amount of money and gets an amount of $854 in 4 years. If both amounts were invested at the same rate (simple interest). What was the sum of money invested ?
A. 670
B. 664
C. 698
D. 744
E. 700
Let the amount invested = p $
Amount of Peter in 3 years = p(1 + 3*r/100) = 815
--> p + 3pr/100 = 815 ...... (1)
Amount of David in 4 years = 0(1 + 4*r/100) = 854
--> p + 4pr/100 = 854 ...... (2)
(2) - (1) gives
--> pr/100 = 854 - 815 = 39
Substitute the value in (1)
--> p + 3*39 = 815
--> p = 815 - 117 = 698 $
IMO Option C
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71% (02:18) correct 
