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Phone plan A charges $1.25 for the first minute and $0.15 for every mi

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Phone plan A charges $1.25 for the first minute and $0.15 for every mi  [#permalink]

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New post 19 Aug 2018, 09:50
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63% (01:33) correct 37% (01:15) wrong based on 113 sessions

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Phone plan A charges $1.25 for the first minute and $0.15 for every minute thereafter. Phone plan B charges a $0.90 connection fee and $0.20 per minute. Which of the following equations could be used to find the length, in minutes, of a phone call that costs the same under either plan?

(A) 1.25 + 0.15x = 0.90x + 0.20
(B) 1.25 + 0.15x = 0.90 + 0.20x
(C) 1.25 + 0.15(x – 1) = 0.90 + 0.20x
(D) 1.25 + 0.15(x – 1) = 0.90 + 0.20(x – 1)
(E) 1.25 + 0.15x + 0.90x + 0.20 = x

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Phone plan A charges $1.25 for the first minute and $0.15 for every mi  [#permalink]

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New post 19 Aug 2018, 11:26
Bunuel wrote:
Phone plan A charges $1.25 for the first minute and $0.15 for every minute thereafter. Phone plan B charges a $0.90 connection fee and $0.20 per minute. Which of the following equations could be used to find the length, in minutes, of a phone call that costs the same under either plan?

(A) 1.25 + 0.15x = 0.90x + 0.20
(B) 1.25 + 0.15x = 0.90 + 0.20x
(C) 1.25 + 0.15(x – 1) = 0.90 + 0.20x
(D) 1.25 + 0.15(x – 1) = 0.90 + 0.20(x – 1)
(E) 1.25 + 0.15x + 0.90x + 0.20 = x


Let 'x' be the number of minutes.
Phone plan A
charges $1.25 for the first minute and $0.15 for every minute thereafter.
So charges=1.25*1+0.15(x-1)

Phone plan B
charges a $0.90 connection fee and $0.20 per minute.
So charges=0.90*1+0.20x

Given, charges for x number of minutes is the same under both the plans.
So, 1.25*1+0.15(x-1)=0.90*1+0.20x
Or, 1.25 + 0.15(x – 1) = 0.90 + 0.20x

Ans. (C)
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Re: Phone plan A charges $1.25 for the first minute and $0.15 for every mi  [#permalink]

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New post 16 Feb 2019, 07:49
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Bunuel wrote:
Phone plan A charges $1.25 for the first minute and $0.15 for every minute thereafter. Phone plan B charges a $0.90 connection fee and $0.20 per minute. Which of the following equations could be used to find the length, in minutes, of a phone call that costs the same under either plan?

(A) 1.25 + 0.15x = 0.90x + 0.20
(B) 1.25 + 0.15x = 0.90 + 0.20x
(C) 1.25 + 0.15(x – 1) = 0.90 + 0.20x
(D) 1.25 + 0.15(x – 1) = 0.90 + 0.20(x – 1)
(E) 1.25 + 0.15x + 0.90x + 0.20 = x


Phone plan A charges $1.25 for the first minute and $0.15 for every minute thereafter.
Let x = total duration of phone call (in minutes)
So, the cost of an x-minute call = $1.25 + ($0.15)(x - 1)

ASIDE: I created the expression ($0.15)(x - 1) because we pay $1.25 for the FIRST minute. So, if x = the TOTAL call time, then x-1 = the time spent AFTER the first minute)

Phone plan B charges a $0.90 connection fee and $0.20 per minute.
Let x = total duration of phone call (in minutes)
So, the cost of an x-minute call = $0.90 + ($0.20)(x)

Which of the following equations could be used to find the length, in minutes, of a phone call that costs the same under either plan?
We need: $1.25 + ($0.15)(x - 1) = $0.90 + ($0.20)(x)

Answer: C

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Brent
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Re: Phone plan A charges $1.25 for the first minute and $0.15 for every mi  [#permalink]

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New post 22 Feb 2019, 16:32
Bunuel wrote:
Phone plan A charges $1.25 for the first minute and $0.15 for every minute thereafter. Phone plan B charges a $0.90 connection fee and $0.20 per minute. Which of the following equations could be used to find the length, in minutes, of a phone call that costs the same under either plan?

(A) 1.25 + 0.15x = 0.90x + 0.20
(B) 1.25 + 0.15x = 0.90 + 0.20x
(C) 1.25 + 0.15(x – 1) = 0.90 + 0.20x
(D) 1.25 + 0.15(x – 1) = 0.90 + 0.20(x – 1)
(E) 1.25 + 0.15x + 0.90x + 0.20 = x


We can create the equation in which x = the number of minutes that equates the charges of the two plans. Plan A charges $1.25 for the first minute and $0.15 for the remaining (x - 1) minutes. Plan B charges a $0.90 fee and $0.20 for all x minutes of the call. Thus, the equation that equates the charges for the two plans is:

1.25 + 0.15(x - 1) = 0.9 + 0.2x

Answer: C
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Re: Phone plan A charges $1.25 for the first minute and $0.15 for every mi   [#permalink] 22 Feb 2019, 16:32
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