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09 Apr 2021, 02:00
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D
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Difficulty:
5%
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Question Stats:
96% (01:19) correct
4%
(00:56)
wrong
based on 53
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Photocopier A, working alone at its constant rate, makes 1,200 copies in 3 hours. Photocopier B, working alone at its constant rate, makes 1,200 numbers of copies in 2 hours. Photocopier C, working alone at its constant rate, makes 1,200 numbers of copies in 6 hours. How many hours will it take photocopiers A, B, and C, working together at their respective constant rates, to make 3,600 numbers of copies?
(A) 2.00
(B) 2.25
(C) 2.50
(D) 3.00
(E) 3.50
(A) 2.00
(B) 2.25
(C) 2.50
(D) 3.00
(E) 3.50
09 Apr 2021, 11:46
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Bunuel
Let's calculate the number of copies that each photocopier copies per hours (use could use a Work=Rate*Time - Table for that):
Copier A: 1200 in 3 hours; Rate = \(\frac{1200}{3}=\frac{400}{1}\) copies/hour
Copier B: 1200 in 2 hours; Rate = \(\frac{1200}{2}=\frac{600}{1}\) copies/hour
Copier C: 1200 in 6 hours; Rate = \(\frac{1200}{6}=\frac{200}{1}\) copies/hour
Now combine their rates:
\(\frac{400}{1}+\frac{600}{1}+\frac{200}{1}=\frac{1200}{1}\) copies/hour, if they work together.
When they copy 1200 copies in 1 hour, they need 3 hours for 3*1200 = 3600 copies
Answer D
