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18 Aug 2015, 13:24
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When positive integer x is divided by positive integer y, the result is 59.32. What is the sum of all possible 2-digit remainders for xy?
560
616
672
728
784
560
616
672
728
784
18 Aug 2015, 22:49
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sahilicecool
First check this post which explains the basics: https://www.gmatclub.com/forum/veritas-prep-resource-links-no-longer-available-399979.html#/2011/05 ... emainders/
59.32 = 59(32/100) = 59(8/25) in lowest terms
The remainders will be 8 or multiples of 8. We need all two digit remainders so we need the sum of all two digit multiples of 8:
Sum = 16 + 24 + 32 + 40 + ....96
= 8 * (2 + 3 + 4...+ 12)
= 8 * (1 + 2+ 3 +.. + 12 - 1) (We add and subtract 1 so that we can use (n*(n+1)/2 formula for sum of first n positive integers)
= 8 * (12(13)/2 - 1)
= 8*77 = 616
Answer (B)
I think there is typo in your question. It should read "... remainders for x/y?"
