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(PLEASE SOLVE THIS PROBLEM, ANYONE!) PS Problem #6. Thx!! :)

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(PLEASE SOLVE THIS PROBLEM, ANYONE!) PS Problem #6. Thx!! :) [#permalink]

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Problem 6.jpg
Problem 6.jpg [ 9.66 KiB | Viewed 855 times ]

In the circle, PQ is parallel to diameter OR, and OR has length 18. What is the length of minor arc PQ?

A) 2pi
B) (9pi)/4
C) (7pi)/2
D) (9pi)/2
E) 3pi

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Location: Africa/Europe
Schools: Kellogg; Ross ($$); Tuck
Re: (PLEASE SOLVE THIS PROBLEM, ANYONE!) PS Problem #6. Thx!! :) [#permalink]

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New post 27 Jul 2009, 00:15
Hey,

That is what I did, but unfortnately I don't find my result among the answer choices.
no mistake when you typed? or maybe there is a flaw in my method....
Attachment:
geom.JPG
geom.JPG [ 23.33 KiB | Viewed 839 times ]

Kudos [?]: 37 [0], given: 6

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Kudos [?]: 26 [0], given: 6

Re: (PLEASE SOLVE THIS PROBLEM, ANYONE!) PS Problem #6. Thx!! :) [#permalink]

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New post 27 Jul 2009, 00:24
madeinafrica wrote:
Hey,

That is what I did, but unfortnately I don't find my result among the answer choices.
no mistake when you typed? or maybe there is a flaw in my method....
Attachment:
geom.JPG


You reasoning is correct, but the arc PQ is DIAMETER*pi/9, not radius*pi/9.

Another way to do this is, after finding that the angle was 40 degrees, you could say that the arc PQ= (40/360)*(18*pi), where (18*pi) is the circumfrence of the circle.


Therefore, the answer is 2pi.


Thanks!

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Re: (PLEASE SOLVE THIS PROBLEM, ANYONE!) PS Problem #6. Thx!! :)   [#permalink] 27 Jul 2009, 00:24
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