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# (PLEASE SOLVE THIS PROBLEM, ANYONE!) PS Problem #6. Thx!! :)

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Joined: 23 Jun 2009
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26 Jul 2009, 21:29
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Attachment:

Problem 6.jpg [ 9.66 KiB | Viewed 952 times ]

In the circle, PQ is parallel to diameter OR, and OR has length 18. What is the length of minor arc PQ?

A) 2pi
B) (9pi)/4
C) (7pi)/2
D) (9pi)/2
E) 3pi
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Re: (PLEASE SOLVE THIS PROBLEM, ANYONE!) PS Problem #6. Thx!! :) [#permalink]

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26 Jul 2009, 23:15
Hey,

That is what I did, but unfortnately I don't find my result among the answer choices.
no mistake when you typed? or maybe there is a flaw in my method....
Attachment:

geom.JPG [ 23.33 KiB | Viewed 936 times ]
Intern
Joined: 23 Jun 2009
Posts: 47
Re: (PLEASE SOLVE THIS PROBLEM, ANYONE!) PS Problem #6. Thx!! :) [#permalink]

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26 Jul 2009, 23:24
Hey,

That is what I did, but unfortnately I don't find my result among the answer choices.
no mistake when you typed? or maybe there is a flaw in my method....
Attachment:
geom.JPG

You reasoning is correct, but the arc PQ is DIAMETER*pi/9, not radius*pi/9.

Another way to do this is, after finding that the angle was 40 degrees, you could say that the arc PQ= (40/360)*(18*pi), where (18*pi) is the circumfrence of the circle.

Thanks!
Re: (PLEASE SOLVE THIS PROBLEM, ANYONE!) PS Problem #6. Thx!! :)   [#permalink] 26 Jul 2009, 23:24
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