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nick_sun
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Amit05
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Bluebird
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I also say it is E

We know:
m>0
X = (m/100)y

we need to know: what is y/x in terms of m
>>> y/x = 100/m
However as you are dealing with percentages you will have to multiply 100/m by 100 = 10000/m
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nick_sun
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Thank you guys! OA is E.
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grad_mba
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quicker way :

assume values !

say y=100 / x=20 => m=20

now for k% of 20 =100 ; k = 500

only E = 10000/m => 10000/20 =500 satisfies the condition !
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KillerSquirrel
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grad_mba
quicker way :

assume values !

say y=100 / x=20 => m=20

now for k% of 20 =100 ; k = 500

only E = 10000/m => 10000/20 =500 satisfies the condition !


Nice ! thanks grad_mba :-D
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gmatnub
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I just came across this question in the book.

I just think that this is a real confusing question. It is not difficult, but the way they want you to set it up and to translate the question into an equation is contradictory to their other similar percentage problems (I don't have the exact examples off the top of my head).

To me "x is m percent of y" translates to x/y = m100 (not m/100). Meaning when x divide y, you get a decimal number (could be greater than or equal to or less than 1), you multiply that number by 100 to get the "percent" annotation.

I know that the OA is E, but the OG explanation is not consistent with their other "percentage" setups.
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netcaesar
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If x= (m/100) y ,

then y= (100x)/m

The question is: y=(?/100)x

Then we can equal (100x)/m =(?/100) x

So 100*100/m = ?

Answer is E



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