Bunuel wrote:
Point A in the xy-coordinate system is shown below. Given two other points B (4a, b) and C (2a, 5b), what is the area of triangle ABC in terms of a and b?
A. 7ab/2
B. 9ab/2
C. 15ab/2
D. 4ab
E. 6ab
Attachment:
GMAT_PS_Magoosh_24000.png
Co-ordinate of the vertices of the triangle ABC are A (a,b), B (4a, b) and C (2a, 5b).
We need base and height in order to determine area of a triangle.
Base=AB=4a-a=3a (Since y-position is constant)
height=5b-b=4b (Distance between point C and intersection point of height with base, since x-position remains constant ,we can substract the y-positions of the two points to get the height)
So, \(Area=\frac{1}{2}*3a*4b=6ab\)
Ans. (E)
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Regards,
PKN
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