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less time consuming way?
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Wanted to share my way of going through this problem:
We have AC = 20, CD = 7, AB = 3. To see what are the possible organizations of A, B, C, and D, I will start analyzing by two pairs - AC/AB and AC/CD. My rationale is that it is easier to think of the organization of these letters when i analyze them in pairs with 1 common point.
1) AC/AB
AC = 20
AB = 3
-> 2 scenarios
a) A_(3)__B______(17)_____C (when B is between A and C)
b) B__(3)___A_______(20)____________C (When B is before A)

2)AC/CD
AC = 20
CD = 7
Again similar to 1)
c) A___(13)_______D___(7)____C (when D is between A and C)
d) A_______(20)____________C___(7)___D (When D is to the left of A and C)


=> Combining a),b),c),d), we have 4 options:
ac) BD = AC - AB + DC = 20 - 3 + 7 = 24
ad) BD = AC - AB - CD = 20 - 3 - 7 = 10
bc) BD = AB + AC - CD = 3 + 20 - 7 = 16
bd) BD = AB + AC + CD = 3 + 20 + 7 = 30

Choose E
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