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Points P, R, M and S lie on the number line shown. The coor
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26 Feb 2013, 08:31
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Points P, R, M and S lie on the number line shown. The coordinate of R is 0. The distance between P and R is 1/3 the distance between P and S. If M is the midpoint of line segment PS, what is the coordinate of P? (1) The coordinate of M is 1.5 (2) The coordinate of S is 6 From the GMAT Question pack 1 Rated: Hard
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Re: Points P, R, M and S lie on the number line shown. The coor
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26 Feb 2013, 08:51
Points P, R, M and S lie on the number line shown. The coordinate of R is 0. The distance between P and R is 1/3 the distance between P and S. If M is the midpoint of line segment PS, what is the coordinate of P? The distance between P and R is 1/3 the distance between P and S > P=1/3*(SP) (the distance between P and R=0 is P and the distance between P and S is SP) > S=2P. M is the midpoint of line segment PS > M=(S+P)/2. (1) The coordinate of M is 1.5 > 1.5=(S+P)/2. We have 2 distinct linear equations (1.5=(S+P)/2 and S=2P) with 2 unknowns, thus we can solve for both of them. Sufficient. (2) The coordinate of S is 6 > 6=2P > P=3. Sufficient. Answer: D. Hope it's clear.
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Re: Points P, R, M and S lie on the number line shown. The coor
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26 Feb 2013, 09:13
Bunuel wrote: Points P, R, M and S lie on the number line shown. The coordinate of R is 0. The distance between P and R is 1/3 the distance between P and S. If M is the midpoint of line segment PS, what is the coordinate of P? The distance between P and R is 1/3 the distance between P and S > P=1/3*(SP) (the distance between P and R=0 is P and the distance between P and S is SP) > S=2P. M is the midpoint of line segment PS > M=(S+P)/2. Thanks! Question tho, are you getting P (because it's to the left of 0) by subtracting PR > P(0) = P ? Then isn't the distance between S and P > S(P) = S+P?
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Re: Points P, R, M and S lie on the number line shown. The coor
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26 Feb 2013, 10:01
DelSingh wrote: Bunuel wrote: Points P, R, M and S lie on the number line shown. The coordinate of R is 0. The distance between P and R is 1/3 the distance between P and S. If M is the midpoint of line segment PS, what is the coordinate of P? The distance between P and R is 1/3 the distance between P and S > P=1/3*(SP) (the distance between P and R=0 is P and the distance between P and S is SP) > S=2P. M is the midpoint of line segment PS > M=(S+P)/2. Thanks! Question tho, are you getting P (because it's to the left of 0) by subtracting PR > P(0) = P ? Then isn't the distance between S and P > S(P) = S+P? Use numbers to test. What is the distance between 3 and 0? It's 3. What is the distance between 3 and 6? It's 6(3)=9.
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Re: Points P, R, M and S lie on the number line shown. The coor
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26 Dec 2015, 17:18
Bunuel wrote: Points P, R, M and S lie on the number line shown. The coordinate of R is 0. The distance between P and R is 1/3 the distance between P and S. If M is the midpoint of line segment PS, what is the coordinate of P? The distance between P and R is 1/3 the distance between P and S > P=1/3*(SP) (the distance between P and R=0 is P and the distance between P and S is SP) > S=2P. M is the midpoint of line segment PS > M=(S+P)/2. (1) The coordinate of M is 1.5 > 1.5=(S+P)/2. We have 2 distinct linear equations (1.5=(S+P)/2 and S=2P) with 2 unknowns, thus we can solve for both of them. Sufficient. (2) The coordinate of S is 6 > 6=2P > P=3. Sufficient. Answer: D. Hope it's clear. Can you please outline step by step how to get S = 2P exactly? Thanks



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Points P, R, M and S lie on the number line shown. The coor
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27 Dec 2015, 04:42
sagnik242 wrote: Bunuel wrote: Points P, R, M and S lie on the number line shown. The coordinate of R is 0. The distance between P and R is 1/3 the distance between P and S. If M is the midpoint of line segment PS, what is the coordinate of P? The distance between P and R is 1/3 the distance between P and S > P=1/3*(SP) (the distance between P and R=0 is P and the distance between P and S is SP) > S=2P. M is the midpoint of line segment PS > M=(S+P)/2. (1) The coordinate of M is 1.5 > 1.5=(S+P)/2. We have 2 distinct linear equations (1.5=(S+P)/2 and S=2P) with 2 unknowns, thus we can solve for both of them. Sufficient. (2) The coordinate of S is 6 > 6=2P > P=3. Sufficient. Answer: D. Hope it's clear. Can you please outline step by step how to get S = 2P exactly? Thanks \(P = \frac{1}{3}*(S  P)\) \(3P = S  P\) \(3P + P = S\) \(S = 2P\)
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Points P, R, M and S lie on the number line shown. The coor
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26 Jan 2016, 08:56
I do it this way: First equation: \(R  P = \frac{1}{3} (S  P)\) \(3R = S + 2P\) since R is zero \(S = 2p\)Second equation: \(\frac{S + P}{2} = M\) \(S + P = 2M\) replace P or S in the equation replacing P \(S\frac{S}{2} = 2M\) \(S= 4M\)or replacing S \(2P + P = 2M\) \(P = 2M\)
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Re: Points P, R, M and S lie on the number line shown. The coor
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05 Mar 2017, 10:30
Option D Let's assume PS = X PM = MS = X/2 PR = X/3; RM = PM  PR = X/6 I) M = 1.5 (lies on Xaxis) Hence, RM = 1.5 = X/6 X = 9. PR = X/3 = 9/3 = 3 R coordinates : 0,0 P coordinates : 3,0 Sufficient II) S = 6 Therefore, RS = 6 = RM + MS = X/3 + X/2 = 2X/3 X = PS = 9 S : 6,0 Hence, P: 3,0 Sufficient Sent from my MotoG3TE using GMAT Club Forum mobile app
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Re: Points P, R, M and S lie on the number line shown. The coor
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20 Apr 2019, 05:22
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Re: Points P, R, M and S lie on the number line shown. The coor
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