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Positive integers

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SVP
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Schools: CBS, Kellogg
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Positive integers [#permalink]

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New post 02 Jun 2009, 19:15
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Q11
Of the three-digit positive integers that have no digits equal
to zero, how many have two digits that are equal to each
other and the remaining digit different from the other two?
A. 24
B. 36
C. 72
D. 144
E. 216
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Kudos [?]: 1342 [0], given: 1

Intern
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Joined: 27 May 2009
Posts: 42

Kudos [?]: 231 [0], given: 3

Re: Positive integers [#permalink]

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New post 02 Jun 2009, 22:03
No of ways selecting similar digits X No of ways to select a different digit X No of ways these can be arranged amongst themselves
9X8X3=216

Kudos [?]: 231 [0], given: 3

SVP
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Joined: 07 Nov 2007
Posts: 1795

Kudos [?]: 1032 [0], given: 5

Location: New York
Re: Positive integers [#permalink]

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New post 02 Jun 2009, 22:06
sondenso wrote:
Q11
Of the three-digit positive integers that have no digits equal
to zero, how many have two digits that are equal to each
other and the remaining digit different from the other two?
A. 24
B. 36
C. 72
D. 144
E. 216



9C1*8C1 * 3!/2! = 216
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Kudos [?]: 1032 [0], given: 5

Senior Manager
Senior Manager
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Joined: 15 Jan 2008
Posts: 281

Kudos [?]: 47 [0], given: 3

Re: Positive integers [#permalink]

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New post 03 Jun 2009, 02:53
yeah.. agree.. answer is 16.. 9*8*3

Kudos [?]: 47 [0], given: 3

SVP
SVP
avatar
Joined: 04 May 2006
Posts: 1890

Kudos [?]: 1342 [0], given: 1

Schools: CBS, Kellogg
Premium Member
Re: Positive integers [#permalink]

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New post 05 Jun 2009, 03:02
Thanks guys,

Full reasonings must be 9*1*8*3=216, also is OA
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Kudos [?]: 1342 [0], given: 1

Re: Positive integers   [#permalink] 05 Jun 2009, 03:02
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Positive integers

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