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# Positive integers

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SVP
Joined: 04 May 2006
Posts: 1773
Schools: CBS, Kellogg

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02 Jun 2009, 19:15
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Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

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Q11
Of the three-digit positive integers that have no digits equal
to zero, how many have two digits that are equal to each
other and the remaining digit different from the other two?
A. 24
B. 36
C. 72
D. 144
E. 216

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Intern
Joined: 27 May 2009
Posts: 36

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02 Jun 2009, 22:03
No of ways selecting similar digits X No of ways to select a different digit X No of ways these can be arranged amongst themselves
9X8X3=216
SVP
Joined: 07 Nov 2007
Posts: 1728
Location: New York

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02 Jun 2009, 22:06
sondenso wrote:
Q11
Of the three-digit positive integers that have no digits equal
to zero, how many have two digits that are equal to each
other and the remaining digit different from the other two?
A. 24
B. 36
C. 72
D. 144
E. 216

9C1*8C1 * 3!/2! = 216
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Senior Manager
Joined: 15 Jan 2008
Posts: 260

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03 Jun 2009, 02:53
yeah.. agree.. answer is 16.. 9*8*3
SVP
Joined: 04 May 2006
Posts: 1773
Schools: CBS, Kellogg

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05 Jun 2009, 03:02
Thanks guys,

Full reasonings must be 9*1*8*3=216, also is OA

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If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.

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Re: Positive integers &nbs [#permalink] 05 Jun 2009, 03:02
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