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arthuro69
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The radius of circum circle of an equilateral triangle = a/sqrt(3). a is the side of triangle.
Here: a/sqrt(3) = 4
a = 4*sqrt(3).
perimeter 3a = 3*4*sqrt(3) = 12sqrt(3).
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arthuro69
What is the perimeter of an equilateral triangle inscribed in a circle of radius 4 ?

A. \(6\sqrt{2}\)
B. \(6\sqrt{3}\)
C. \(12\sqrt{2}\)
D. \(12\sqrt{3}\)
E. \(24\)

source: readyforgmat.com

All you need to know about triangles for the GMAT: math-triangles-87197.html

Hope it helps.
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Let x be the side of triangle.

Using cosine rule:
(x/2)/R = cos 30
=> x = 2Rcos 30 = 4√3
=> Perimeter = 3X = 12√3
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arthuro69
What is the perimeter of an equilateral triangle inscribed in a circle of radius 4 ?

A. \(6\sqrt{2}\)
B. \(6\sqrt{3}\)
C. \(12\sqrt{2}\)
D. \(12\sqrt{3}\)
E. \(24\)

source: readyforgmat.com

way simpler to simply know a formula :

Whenever a Circle circumscribes an equilateral triangle, the The radius of the circle can be defined by : Radius = \(\frac{Side Of The Triangle}{\sqrt{3}}\).

that way, if we solve the problem : 4 = \(\frac{s}{\sqrt{3}}\) . Hence, side = \(4\sqrt{3}\).

Now, the perimeter = 3 x \(4\sqrt{3}\) = 12\(\sqrt{3}\) .
The answer is the option D.
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For equilateral triangle the radius of the circumscribed circle R = Side * \(Root 3/3\)
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