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rajathpanta
Joined: 13 Feb 2010
Last visit: 24 Apr 2015
Posts: 142
Given Kudos: 282
Status:Prevent and prepare. Not repent and repair!!
Location: India
Concentration: Technology, General Management
Schools: AGSM '15 YLP '16 IIMC (PGPEX) Melbourne '15
GPA: 3.75
WE:Sales (Telecommunications)
Updated on: 30 Oct 2012, 09:45
Originally posted by rajathpanta on 30 Oct 2012, 09:09.
Last edited by Bunuel on 30 Oct 2012, 09:45, edited 1 time in total.
Last edited by Bunuel on 30 Oct 2012, 09:45, edited 1 time in total.
Renamed the topic and edited the question.
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
70% (01:08) correct
30%
(01:21)
wrong
based on 364
sessions
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What is the greatest distance between two points in a cylinder where the area of the base is 9 pi and height is 5?
A. \(\sqrt{34}\)
B. \(\sqrt{48}\)
C. \(\sqrt{61}\)
D. \(\sqrt{76}\)
E. \(\sqrt{106}\)
A. \(\sqrt{34}\)
B. \(\sqrt{48}\)
C. \(\sqrt{61}\)
D. \(\sqrt{76}\)
E. \(\sqrt{106}\)
30 Oct 2012, 09:21
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rajathpanta
If radius of base is r then pi*r^2 = 9pi
=> r =3
The greatest distance would be between A and B. On different sides of circularr faces
=sqrt (6^2 +5^2)
=sqrt 61
Ans C it is.
Attachments
Screenshot01 31-Oct-12 00.24.jpg [ 9.3 KiB | Viewed 10018 times ]
30 Oct 2012, 09:43
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rajathpanta
Look at the diagram below:
Attachment:
Cylinder.png [ 4.99 KiB | Viewed 9973 times ]
Now, since \(area=9\pi=\pi{r^2}\), then \(r=3\)and \(d=6\) --> \(x=\sqrt{5^2+6^2}=\sqrt{61}\).
Answer: C.
Hope it's clear.
P.S. Please do not shorten the words in the question. Thank you.
