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15 May 2013, 00:31
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Difficulty:
35%
(medium)
Question Stats:
74% (02:16) correct
26%
(02:56)
wrong
based on 288
sessions
History
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Each of the products produced yesterday was checked by x or y. 0.5% of the products checked by x are defective and 0.8% of the products checked by y are defective. If the total defective rate of all the products checked by x and y is 0.75%, what fraction of the products was checked by y?
A. 3/5
B. 5/6
C. 7/11
D. 4/5
E. 5/8
A. 3/5
B. 5/6
C. 7/11
D. 4/5
E. 5/8
15 May 2013, 02:59
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navigator123
This is a allegation problem.
We can use a shortcut.
See the attachment for the shortcut.Its a simple one
So X/Y = 0.05/0.25 = 1/5
Therefore the fraction of products checked by Y = 5/6
Attachments
File comment: The shortcut
untitled.JPG [ 4.43 KiB | Viewed 6285 times ]
15 May 2013, 00:47
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navigator123
The easiest way to do these types of questions is to look at the difference between x and y on a number line. x is at 0.5 and y is at 0.8, and together the average is 0.75. This means that every product checked by x brings down the average by 0.25 and every product checked by y brings up the average by 0.05. To balance these two out, y needs to check 5 products for every time x checks 1 product. Hence 1/6 of total checked by x and 5/6 of total checked by y.
Algebra works too but the number line strategy gets you the correct answer quickly. If you practice doing that, this is a 1-minute question, from starting to read to clicking "next".
Hope this helps!
-Ron
