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joemama142000
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Jennif102
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in the same manner to Himalaya, firstly express y=-3/5x+30
becoz 30 is an integer, to get y an integer, -3/5 x must be an integer ----> x must be multiples of 5, value of x ranges from 0, 50 inclusively
from 0 to 50, the possible values of x which are multiples of 5 are : 0, 6,10,15,20,25,........50 ...there're 11 numbers in all.
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TeHCM
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Jennif102
I don't get the question...it's asking how many points on the line are both integers? Meaning the point equals (30,50) or (50,30)...is that what it's asking?


The question is asking within that line, how many coordinates would have integers in it? (Just by looking at the line, one of the coordinates could be (49.5, 2.1), or (25.5, 14.9)...)

We write coordinates as (x, y). So how would we get (x,y) to be integers? We find out the equation of the line.

We need to find the slope first. Equation of the line y=mx+b, m=slope

m=changes in y/changes in x=(0-30)/(50-0)=-(3/5), y-intercept is 30

y=-(3/5)x+30

In order to get x to be an integer, x needs to be multiples of 5. X cannot exceed 50 as it is the x-intercept.

There are 11 multiples of 5 from 0-50......
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rianah100
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I drew a rectangle with the above pic. Then, I will have a total of 1500 points, exclude the points at which the line intersects x and y axes. you get 1498. Divide that by 2- answer is 749.



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