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25 May 2016, 04:41
Kudos
Bookmarks
E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
91% (00:51) correct
9%
(01:15)
wrong
based on 181
sessions
History
Date
Time
Result
Not Attempted Yet
What is the sum of the different positive prime factors of 660?
A. 5
B. 10
C. 15
D. 17
E. 21
A. 5
B. 10
C. 15
D. 17
E. 21
25 May 2016, 06:13
Kudos
Bookmarks
Prime factorization of 660
=66 * 10
=6*11 * 10
=2*3 * 2*5 * 11
=2^2 * 3 * 5 * 11
Sum of the different positive prime factors of 660 = 2+3+5+11
=21
Answer E
=66 * 10
=6*11 * 10
=2*3 * 2*5 * 11
=2^2 * 3 * 5 * 11
Sum of the different positive prime factors of 660 = 2+3+5+11
=21
Answer E
25 May 2016, 08:06
Kudos
Bookmarks
Bunuel
\(660\) = \(2^2\) x \(3^1\) x \(5^1\) x \(11^1\)
Sum of diff positive prime factors = 22 ( 2 + 3 + 5 + 11 )
Hence answer will be (E) 21
