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Updated on: 13 Nov 2019, 17:04
Originally posted by BrentGMATPrepNow on 29 Oct 2016, 09:39.
Last edited by BrentGMATPrepNow on 13 Nov 2019, 17:04, edited 1 time in total.
Last edited by BrentGMATPrepNow on 13 Nov 2019, 17:04, edited 1 time in total.
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E
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Difficulty:
15%
(low)
Question Stats:
82% (01:31) correct
18%
(01:47)
wrong
based on 422
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A bag contains blue, red and green marbles only. If the ratio of blue marbles to red marbles is 4 to 5, and the ratio of green marbles to blue marbles is 4 to 3, what is the minimum number of marbles in the bag?
A) 12
B) 16
C) 28
D) 41
E) 43
* Kudos for all correct solutions
A) 12
B) 16
C) 28
D) 41
E) 43
* Kudos for all correct solutions
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29 Oct 2016, 10:12
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b:r = 4:5
b:g= 3:4
b:r:g = 12:15:16
Minimum total = 12+15+16 = 43
E
Sent from my iPhone using GMAT Club Forum mobile app
b:g= 3:4
b:r:g = 12:15:16
Minimum total = 12+15+16 = 43
E
Sent from my iPhone using GMAT Club Forum mobile app
29 Oct 2016, 10:19
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GMATPrepNow
let's call the number of marbles r, b and g
from the question we can easily get that \(b=\frac{4}{5}*r\) and \(b=\frac{3}{4}*g\)
combining the two equation we have that \(\frac{4}{5}*r=\frac{3}{4}*g\) and therefore, \(r=\frac{15}{16}*g\)
as both r and g must be integers r must be 15 and g must be 16.
from one of the first two equations we can find by sobstitution that b=12
\(15+16+12= 43\)
answer E
