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Question Stats:
55% (02:24) correct 45% (02:14) wrong based on 1352 sessions File comment: Here is another graphical approach.
The blue graph represents |x-6| and red graph represents |3x+6| and these two graphs meet each other at x=0 and x=-6
For |x-6| to be greater than |3x+6| the blue graph should be above red graph. So our solution should be -6<x<0 i.e. -1,-2,-3,-4,-5.
Experts please comment if this approach is correct. Also I tried applying the same approach to 3 modulus equations but it is not so handy as it is here.. Please suggest some method for 3 modulus problems as |x – 8| + |5 – x| > |x + 7|
Graph1.PNG [ 34.52 KiB | Viewed 29288 times ]
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Hi Generic [Bot],
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