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12 Feb 2018, 00:27
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A
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In the figure above, the coordinates of points P and Q are (6,0) and (0,6), respectively, What is the area of the circle O ?
(A) \(36\pi\)
(B) \(12\pi\)
(C) \(9\pi\)
(D) \(6\pi\)
(E) \(3\pi\)
Attachment:
2018-02-12_1125.png [ 8.45 KiB | Viewed 2296 times ]
12 Feb 2018, 02:08
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Point O has the co-ordinates (6,6)
Now, OP is \(\sqrt{(6-6)^2 + (6-0)^2} = \sqrt{36} = 6\)
Similarly, OQ is \(\sqrt{(6-0)^2 + (6-6)^2} = \sqrt{36} = 6\)
Hence, Point O will be the center of the circle and radius is 6.
Therefore, the area of the circle with radius 6 is \(\pi*6^2 = 36\pi\)(Option A)
13 Feb 2018, 18:02
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Bunuel
Looking at the diagram, we see that the radius of circle O is 6, so the area is 6^2 x π = 36π.
Answer: A
