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18 May 2018, 02:04
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
34% (02:51) correct
66%
(02:31)
wrong
based on 77
sessions
History
Date
Time
Result
Not Attempted Yet
What is the radius of given circle
A. \(\sqrt{3}+1\)
B. \(\sqrt{3}+2\)
C. \(\sqrt{3}+3\)
D. \(4\)
E. \(2\sqrt{3}\)
Radiuscircle.PNG [ 95.82 KiB | Viewed 4338 times ]
A. \(\sqrt{3}+1\)
B. \(\sqrt{3}+2\)
C. \(\sqrt{3}+3\)
D. \(4\)
E. \(2\sqrt{3}\)
Attachment:
Radiuscircle.PNG [ 95.82 KiB | Viewed 4338 times ]
18 May 2018, 02:48
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Concepts used:
1) Sum of 2 sides in a triangle is greater than 3rdside.
2) Pythagoras theorem
3) Angle in a semicircle is 90 deg.
Solution:
Join AC
Now, Consider triangle ACD
AC<AD+CD
AC<2+2
AC<4
In triangle ABC
AB^2 +AC^2 = BC^2
4^2+AC^2= BC^2
Since AC<4
BC^2<4^2+4^2
BC^2 <32
BC<4*root2
Radius = BC/2 <2*root2
R< 2*1.414
R< 2.828
Only Option 1 is less than 2.8. Hence A is the answer
1) Sum of 2 sides in a triangle is greater than 3rdside.
2) Pythagoras theorem
3) Angle in a semicircle is 90 deg.
Solution:
Join AC
Now, Consider triangle ACD
AC<AD+CD
AC<2+2
AC<4
In triangle ABC
AB^2 +AC^2 = BC^2
4^2+AC^2= BC^2
Since AC<4
BC^2<4^2+4^2
BC^2 <32
BC<4*root2
Radius = BC/2 <2*root2
R< 2*1.414
R< 2.828
Only Option 1 is less than 2.8. Hence A is the answer
Attachments
IMG_20180518_143024.jpg [ 310.02 KiB | Viewed 4042 times ]
19 May 2018, 13:09
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How do we find the measure of AC?
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Posted from my mobile device
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